how can i remove redundant sentences from text in richtextbox i.e. exactly same sentences in all text or Sentences that contains two or less than two different words as shown in example one and two.
For exapmle
sentence one: i am john and i am a student. sentence two: i am stewert and yes i am a student.
Example two
Sentence one: i am john and i am a student. Sentence two: i am john and i am a student.
"by removing means sentence two should b remove."
example one has only two differences that is consider as redundant too while example 2 is exact copy. so both should b removed. t
I am trying to query fields in a where clause using LINQ to SQL and for some reason I cannot figure out why it doesn't work:
var qryGetMonsterID = (from students in dbContext.tblStudentPersonals where (students.givenname.Equals(fn)) && (students.familyname.Equals(ln)) && (students.middlename.Equals(mn)) && (students.email.Equals(e)) select students);
The returned SQL Syntax is:
SELECT [t0].[monsterid], [t0].[givenname], [t0].[middlename], [t0].[familyname], [t0].[homeaddress], [t0].[city], [t0].[state], [t0].[postal], [t0].[primaryphone], [t0].[secondaryphone], [t0].[email], [t0].[username], [t0].[lastmodified], [t0].[modifiedby] FROM [dbo].[tblStudentPersonal] AS [t0] WHERE ([t0].[givenname] = @p0) AND ([t0].[familyname] = @p1) AND ([t0].[middlename] = @p2) AND ([t0].[email] = @p3)
Not sure but the values for middle name could be null - because not everyone has a middle name and the same is true for e-mail.
I have two random numbers which are generated and are related to each other (representing x and y co-ordinate). These random numbers are generated within a specified range: (-range, +range).
I want to categorize these values in a (2-dimensional) grid. The grid size is not definite and so can be varied by the user would be in the order of 400 x 400. (e.g., think CCD detector). For each random number pair (x, y) I want to store a hit (a plus one) in the corresponding grid reference.
In the order of 500,000 related random numbers (x and y) are to be generated and the position recorded according to grid reference. So code needs to be fast.
I need counting the number of words in this input (use isspace( ) to find breaks between words), the phrases, and the sentences. Here is my code so far:
#include <iostream> #include <string> #include <cctype> int main() { std::string result ; std::string line ;
I need to extract full sentences from a file and the save them in a set. I tried getline to get a full line and then removed the characters after the period. This method doesn't work too well if the other half of the sentence is on another line. How should i fix this?
After I have compiled and executed code below, and I have made an input of a string, the while loop takes over the control and outputs an endless flow sentences. How can I make sure when an input of string is made, such a thing does not happen? In Python, one can make a type check by the use of type() command, but such a command does not exist in C, so how can I prevent an endless output in case a string input is made by the user?
(The code below is supposed to check whether the number entered by the user is divisible by 7 or not.)
#include <stdio.h> int main() { int a = 0; printf("Input a number!"); while (1 < 2){ scanf("%d", &a); if (a % 7 == 0) {
I have got an assignment. It is about comparing two files one file has sentences and the other abbreviations. so far i have managed to compare the abbreviations which appear in the sentence and erase punctuation linked to abbreviations.
However I am currently stuck on putting the punctuation back in when outputting the file. I am also stuck with replacing matching words in the sentences with the expanded abbreviations. Not sure which code to show. but sentences and abbreviations are below.
ABBREVIATIONS
Aberd Aberdeen admin administration approx approximate Austral Australia div division Capt Captain Comdr Commander e east HQ Head Quarters m metres mil million mt Mount n north NATO North Atlantic Treaty Organisation NSW New South Wales pop population s south sq square w west
Text file
NATO troops were on exercise in Aberd Capt Jones of the first div told Comdr Frank that his troops were near the E flank of the NATO forces. Complaining about the amount of Admin, Capt Jones radioed the NATO HQ asked for navigation relative to the HQ. The Captain then left.
For example the abbreviation "Aberd" in the sentence above needs to be replaced with Aberdeen from the abbreviations file. I need the last part of the abbreviation not "Aberd Aberdeen" need just "Aberdeen". Hope the info is understandable.
I'm trying to get the hang of the declaration and use of char. I'm trying to write a program that reads sentences from the user and changes them based on their character choices, I keep getting load of compiler errors.......am I off to a good start or am I way off?
#include<iostream> #include<string> #include<cstring> #include<cctype> using namespace std; int main() { char *quit*; char sentance [100];
Code: /* generals is the first array. Max 10 elements. numGenerals is the element count of generals.
genBuff is the second array; it is to be checked/pruned. genCount is the element count of genBuff. genBuff will be a max of 171, but be pruned to no more than 10, and no more than the complement of the element count of generals. */
[Code] ....
(I do have comments in the actual source, different from above).
I have two int arrays. They hold values from 0 to 170. The first one will never be more than 10. The second will be at most 171, but will be whittled down to at most 10, usually less. 171 is worst case, most users of this particular program will probably be reasonable and not try to add all 171 (max is 10 anyway). The first array is the original array. The second array is a temporary array. Any value in the second array that is also found in the first array, is removed from the second array, since all values in the first one must be unique. After this pruning process, both arrays will collectively contain no more than 10 unique elements; the elements from the second will be added to the first.
So right now I have three nested loops. I figured with the miniscule array sizes it wouldn't be a big deal. I can think of a way to remove one or two of them, but I want to be sure that I'm still writing clean, legible, good-practice code. The first loop walks through the first array. For each element in the first array, there is a second loop to walk through the second array to check for duplicates. If a duplicate is found, the third loop walks through the second array to overwrite the duplicate while preserving the second loop's position (j).
Is this dumb? I know that the big O gets worse and worse the deeper you go with nested loops. Even though the arrays are really tiny, is this still a thing to avoid?
The following 2 codes are almost identical, only that the switch statements are slightly different. The 2nd code has the issue of requiring an additional enter key to be pressed when I enter '3' as input to exit the program.
Working code :
Code:
#include <stdio.h> #include <ctype.h> #include <string.h> void clearKeyboardBuffer() { int ch; while ((ch = getchar() != '
I know how to remove digits in number from right to left.For example: the number 319. If I do (number /= 10), I get 31.how can I remove digits in number from left to right.For example: the number 319. If I will do something, I will get the number 19.
class List; List *deletezeroendlist(List* L); class List { public: intdigit; List*nextDigit; public: List():digit(0), nextDigit(NULL){} List(int d, List *next):digit(d), nextDigit(next){}
I have tried many different ways but it is still not the answer / perform the function List *deletezeroendlist(List* L)
Below is my .h file and the code below that is my function that I'm having troubles with. Its suppose to take in a users topic and see if that topic exists, if it does exist then find the keyword, commentcompare will find where that keyword is and delete the comment. However its not deleting anything and its returning temp is NULL.
class comment //adds a comment { public: comment(char * create_comment);
How can I remove an element in a list when I have only an iterator that points to the object I want to remove. Is there a build in command? remove() takes an object reference as its argument. Is it possible to convert the iterator into a pointer type so it can be deferenced and passed to remove?
This is the code I am working on:
//player.cpp void Player::CheckCollectableCollisions(std::list<Collectable>& c) { std::list<Collectable>::iterator i = c.begin(); while(i != c.end()) { if (Collider::CheckCollision(pNodes_.front().getLocation(), i->getLocation()))
I am trying to remove the first digit so if the user enters 12345 it should output 2345 the code i have works only for removing the last digit how would i go about removing the first one?
#include <iostream> using namespace std; int removeFirst(int n); int main(){ int n, m; cout << "enter number" << endl;
Im supose to use <>bool removeTile(char, int, int, char[])<> to do this "function that takes in the choice (D or S) and the two dice numbers and the board as input arguments. When the move is legal and the tile is available for removal, it removes the tile according to the choice by marking the tile as ‘X’. Returns true if the move is successful."