C++ :: Struct Output Using A Loop?
Nov 6, 2013
trying to output my struct to a for loop. I understand how to output the struct but not into a for loop.
#include "stdafx.h"
#include <string>
#include <iostream>
using namespace std;
struct Date {
int day;
int month;
int year;
[code]....
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May 11, 2014
My address book will be simple, and the thing's that I'm expecting to use in it are :
Pointers, Linked Lists
Malloc
Structs
Typedefs
Makefile, header file
Putting functions into different program files
I have started the program trying to create a struct, and getting it working with a couple of entries before going onto user input and splitting it up.
Code:
#include <stdio.h>
#include <stdlib.h>
int main(void) {
// Struct type address book. Just a name, a number and a pointer
[Code] .....
I'm a bit lost at this point... My knee jerk thought is to create a for loop, and cycle through the list.
I'm not sure how this would apply to this though? Without using the familiar type of print loop such as :
Code:
for (i = 0; ;i++) {
printf("%i
", array[i];
}
I'm thinking that I need to create a temporary struct that can be used to assign the value of the next struct in the list, and then somehow print from that....
I'll try and write the logic out :
while temp != NULL (The last node value is assigned NULL to show us where the end of the list is)
create a temporary pointer that can be used to keep track of where we are in the list.
print out the current entry name and number
then assign the temp pointer value to the * next of the current struct. So if we are in entry1 the *next should be the address of entry 2.
Print out entry 2 name and number, assign entry 2 next to the temp value.
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Jul 21, 2013
is it possible to output like this using only one loop? if yes, how?
target output Code: ABCDE
EDCBA here is my code but using one loop im not getting my target output Code: #include <stdio.h>
main()
{
int x, y;
for(x='a', y='e'; x<='e'; x++, y--)
{
printf("%c
%c", x, y);
}
getch();
}
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Jun 19, 2014
As I was testing it, the program suddenly stopped giving an output. Here is the code:
#include <iostream>
using namespace std;
int main() {
cout << "Ten people ate breakfast with you this morning. Each of them " <<
"had pancakes.
Please enter how many pancakes each of the ten people " <<
"ate.
" << endl;
[Code] ...
The while loop after int glutton does not work and seems to stop the program. I replaced the "glutton" in the cout with "testing testing" and it still did not work. However, when I commented out the loop, it appeared. Finally, it can't be what's inside the loop, because I commented that out too, and it still didn't work.
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Nov 14, 2014
Something is wrong with option 1. For some reason it adds 1, 2, 3, 4 ... 5 onto the output and I can't think why. Here is a screenshot.
Also how can I make the output a little neater? I tried to use but it just looks horrible.
I had linked the source code! Why is there no edit button?!
#include<iostream>
using namespace std;
int main(){
int option;
cout << "Welcome to my program. Please select a following option.
[Code] .....
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Jan 23, 2014
so i got this piece of code today having some slight errors with it, how its actually done as i want to know where i have gone wrong here is the code .. Using a for loop to input and output array values
*/
#include <stdio.h>
int main(void) {
/* Declare an array of integers */
int Grades[5];
int nCount;
/* Populate the array */
for(nCount = 0; nCount < 5; nCount++)
[Code]...
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Feb 28, 2013
What does the following nested loop output ?
count = 1;
while (count <= 11) {
innerCount = 1
while innerCount <= (12 - count) / 2) {
cout << " ";
innerCount++;
} innerCount = 1;
while (innerCount <= count) {
cout << "@";
innerCount++;
} cout << endl;
count++;
}
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Jul 30, 2014
[URL] when I try to write my output to a file. I am building a life insurance premium calculator with c++. What my calculator does is read in a text file called "policies.txt" containing a number of different policies. For example:
Pol1 M N 20 100000 1 .04 99
Pol2 F S 30 100000 1 .05 99
Pol3 M S 72 750000 1 .03 99
Pol4 F N 45 1000000 1 .05 99
And using this, it creates a single premium. Once the calculator calculates the premium of each policy, I want it to write out the premium amount of each policy to a textfile called "output.txt". The problem is that when I check my "output.txt" file, only the premium for the last policy shows up. It only reads:
Premium for Pol4 is 220384
When I want it to read:
Premium for Pol1 is 14101.6
Premium for Pol2 is 14221.2
Premium for Pol3 is 582391
Premium for Pol4 is 220384
How come only the last policy is showing up? and is there any way to make all four policies appear in my output text file? Here is my code:
double ratesmn[86] = {
#include "MaleNonSmoker.txt"
- 1
};
[Code]....
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Feb 4, 2014
I wanted to display the correct output by using a for loop at the end of my code, but for some reason it's not working correctly.
#include <iostream>
using namespace std;
int main() {
int* ipArray[3];
for(int i = 0; i < 3; i++) {
ipArray[i] = new int [5];
[Code] .....
What I wanted to do is pretty much match my 1st out put like 0 1 2 3 4 but my 2nd output only outputs 24's and I don't know why
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Mar 1, 2015
So I'm having trouble with my code. Got it to work, but having issues in terms of indenting my increment. For this example, I will use * as whitespaces.
Expected output:
0
*1
**2
***3
Your output:
0
*1
**2
***3
*****
The expected output has no extra whitespaces, but mine does. What am I doing wrong?
#include <iostream>
using namespace std;
int main() {
int userNum = 0;
int i = 0;
int j = 0;
for(i =0; i <= userNum; i++){
[Code] ....
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Feb 21, 2013
How to fix this when i run the program and enter my name then output my name in vertical position using the for loop and press enter the program do not stop
#include<stdio.h>
#include<conio.h>
#include<dos.h>
main() {
char name,n;
clrscr();
printf("Enter Your Name:");
scanf("%c",&name);
[Code] ....
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Nov 21, 2014
My loop is outputting data incorrectly. I have inbound web data that come in sets of 7. I am trying to in insert the 7 records into a vector and then display the vector content followed by a new line.
Code:
char buff[BUFSIZ];
FILE *fp = stdout;
char * cstr = buff;
vector<std::string> vrecords;
while(std::fgets(buff, sizeof buff, fp) != NULL){
for(int i = 0; i < 6; ++i){
[Code] ....
expected output:
Found buy!
198397652
2014-11-14 15:10:10
Buy
0.00517290
0.00100000
0.00100000
0.00000517
[Code] ....
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Aug 31, 2013
I am trying to code a partition quicksort but the problem here is at the output is in an infinite loop:
The input : 4 3 5 7 2
The expected output : 2 3 4 5 7
But my output is infinite :
2 3 4 5 7
2 3 4 5 7
2 3 4 5 7
.
.
and so on
[Code:
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
/* Head ends here */
void partition(vector <int> ar) {
[Code] .....
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Jun 12, 2014
Basically I'm supposed to use a while loop to generate a random number and use a switch statement to output the appropriate information. I feel like I'm missing a few things that are very simple.
The errors are:
warning C4244: 'argument' : conversion from 'time_t' to 'unsigned int', possible loss of data
warning C4700: uninitialized local variable 'randomNumber' used
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
using namespace std;
int main(){
int i = 0;
unsigned int randomNumber;
[Code] .....
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Jan 24, 2014
I have this code that im stuck on what i need to do is Extend the code such that when it starts the user is asked to input values to specify each of the three ranges before moving on to accept and tally the main values how do i do that Using a for loop to input and output array values Also calculate the average
*/
#include <stdio.h>
int main(void)
{
/* Declare an array of integers */
int Grades[5];
int nCount;
int nTotal = 0; /* Declare and initialise the value */
float fAverage;
[Code]...
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Sep 14, 2014
#include <stdio.h>
#define MAX_USERS 20
struct {
char ID[10];
char Name[40];
int Pos;
[Code] .....
I was attempting something weired with address to move data around when I discovered that the size of the array is not what I expected. I am passing this structure as &Users to a function that declares it as a void *, then I can deal with chunks of data (memmove) and not have to worry about index or things like that. However...sizeof is returning something I do not understand.
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Mar 9, 2015
I need to write a program to input 6 temperatures in degrees Fahrenheit and output it in degrees Celsius. I used a for loop but it keeps giving me 0 as the output whenever I enter a temperature...
Code:
#include <stdio.h>
#include <math.h>
int main() {
double farenheit,celsius;
for(int i=0; i<6; i++) {
printf("Enter temperature in degrees farenheit: ");
scanf("%lf",&farenheit);
celsius = (5/9)*(farenheit-32);
printf("Temperature in degrees celsius: %lf ",celsius);
} }
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Feb 28, 2015
Im having trouble creating a struct within a struct node. the program suppose to hold students firstname, lastname, and gpa in a node therefore creating my linked list. Line 26 keeps saying that cannot convert parameter 2 from 'studentType to std::string
#include <iostream>
#include <string>
using namespace std;
struct studentType{
string firstname;
string lastname;
double gpa;
[code].....
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Jun 5, 2012
"
#include <stdio.h>
struct datastructure {
char character;
};
void function(struct datastructure** ptr);
[Code] ....
These codes give these errors:
error: request for member 'character' in '* ptr', which is of non-class type 'datastructure*'
error: request for member 'character' in '* ptr', which is of non-class type 'datastructure*'
These errors are related to
"
*ptr->character='a';
printf("Ptr: %c",*ptr->character);
"
I want to access "character" data inside the structure "trial" by a pointer to pointer "ptr" inside function "function",but I couldn't find a way to do this.
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Mar 9, 2012
I just read and have known for a while that classes are private (members and inheritance) by default and structs are public. But my question then comes what if.. a struct inheriting from a class or a class inheriting from a struct?
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Oct 13, 2014
We are making a program--but every time we input a value for scanf, the following for loop does not work and the program quits without displaying the for loop's function. We are not getting any errors.
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Feb 15, 2015
I have tried to submit this topic before but i didn't submit my whole code and it was removed. So here it is. All I am trying to do is load form2 from form1 then back to form1 from form2 for a certain number of times the get out of the loop. I am new to C-Sharp and it seems as though I cant seem to figure out a way to do this.
Here is form1 and form2 code. I have commented out a few things I have tried.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
[Code]....
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Jul 1, 2013
Code:
#include <stdio.h>
#include<ctype.h>
void try5t(){
char choice;
int choiceint;
[Code] .....
Loop is repeated an additional time as shown in the screenshot:
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Feb 20, 2014
Given a for loop:
int i;
for(i = 0; i < 1000; i++)
;
How many nanoseconds, or microseconds or milliseconds does it take for each iteration? And why do some use it as a timer mechanism?
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Apr 19, 2014
I already made a nested for loop into a while loop (below this) and now I'm trying to make the outer for loop into a do while loop, but it's not working.
#include <iostream>
using namespace std;
int main () {
int len;
int j;
int i;
[Code]....
And I can't make this code do the same thing. It stops after one loop, instead of continuing to the end. Why won't the loops continue?
#include <iostream>
using namespace std;
int main(){
int len;
cout << "Enter a number: ";
[Code] ....
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Mar 25, 2012
I need to convert the following while loop:
count = 1;
while (caloriesForItem != 0, count != numberOfItems )
{
cout<<"Enter the calories: ";
cin >> caloriesForItem;
totalCalories += caloriesForItem;
count++;
}
This is what I have come up with:
totalCalories += caloriesForItem;
for (count = 1; caloriesForItem != 0; count != numberOfItems)
{
cout<<"Enter the calories: ";
cin >> caloriesForItem;
count++;
cout << "Total calories eaten today = " << totalCalories << endl;
}
However the output is not the same?
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