I need to remove a char from string that found ;
For example : string- abcdfe
the char ch is - c
and the return new string is : abdfe.
I did as follow:
void removeChar(char string2[SIZE], char ch) {
char input= 'a'; // for example replace something
int i=0;
if(string2[i]== ch && string2[i]!='/0') {
string2[i]= input;
}
i++;
}
and in the main : I only called to this function above and print string.
I've to do a function that removes char(input by user) from string , only if it appeared and to reduce spaces.
for instance: string = abcabcd ; and the char= c/
the return string is : ababd
void removeChar(char string2[SIZE], char ch) {
//---NOTE--- its not completely works - there is a problem i.
int read = 0, write = 0;
[Code].....
int index = -1;
string NewStr = null;
char[] lower = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
char[] upper = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
foreach (char c in str)
[Code]....
The code above loops through a string and for each character checks to see if it is a lower case character, then checks to see if it an upper case. It then removes it if it is. Leaving only the numbers.
However, it reuses the same string the entire time, never updating the string so it always finds the same (first) character.
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[Code]....
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[Code].....
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[Code].....
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Code:
//ch11_9.c
//remove_spaces(char* given_string)
#include <stdio.h>
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#include <string.h>
#include <stdlib.h>
char* remove_spaces(char *given_string){
[Code]...
I need to make a function that removes a function in a c-string. This is what I have:
#include <iostream>
using namespace std;
char removeCharacter (char *str, char c)
{
[Code].....
I want to remove the folder name in a string example C:/test/desktop/new folder/test.xls.i want the string "test"alone and folder may vary.
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Code:
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[Code]...
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[Code] ....
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[URL] ....
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[Code] ....
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