I'm practicing so I wrote this simple program that suppose to add and divide two numbers. It does that but the result comes out with a 0 at the front and don't know why.
#include<iostream>
using namespace std;
int main()
{
int a ,b;
int result;
a = 0;
b = 0;
[Code]...
The problem is that you have a set of numbers and you need to divide that set into two subsets where the difference between the sums of the subset is minimal.
Example: a set of numbers {1,5,9,3,8}, now the solution is two subsets, one subset with elements {9,3} and the other {8,5,1} the sum of the first one is 13 and the sum of the second is 13 so the difference between the sums is 0. The result shows the difference between the sums.
Another example: a set of numbers where the difference between the subsets cannot be zero, {9 51 308 107 27 91 62 176 28 6}, the minimal difference between the two subsets is 2.
I want to know how the function finds the two subsets, it works great because I've tested it for up to 300 inputs which sum adds up to 100,000.
Code:
#include <iostream>
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <limits.h>
using namespace std;
int BalancedPartition ( int a[] , int n ) {
[Code] ....
Create a program that adds, subtracts, multiplies, or divides two integers. The program will need to get a letter (A for addition, S for subtractions, M for multiplication, or D for division) and two integers from the user. If the user enters an invalid letter, the program should display an appropriate error message before the program ends. If the letter is A (or a), the program should calculate and display the sum of both integers. If the letter is S (or s), the program should display the difference between both integers. When calculating the difference, always subtract the smaller number from the larger one. If the letter is M (or m), the program should display the product of both integers. If the letter is D (or d), the program should divide both integers, always dividing the larger number by the smaller one."
And here is the test data. I am posting the results from my desk-check table.
operation first integer second integer answer
A 10 20 30
a 45 15 60
S 65 50 15
s 7 13 6
G -1
M 10 20 200
d 45 15 3
d 50 100 2
Then, I transferred my program into a source file. Here it is:
//Exercise16.cpp - display answer of two integers
#include <iostream>
using namespace std;
int main() {
//declare variables
int firstInteger = 0;
[Code] ....
After putting in the data, everything worked fine, except the last two operations, which are M (multiplication) and D (division). All the answers for the last two operations essentially give me a 0.
i was suppose to write a program that gives a divide error but output is not showing anything like it.I am using orwell devc++ 5.4.2 and all the default built tools(gcc compiler etc.) with default settings.so, what should i do to see this error?
Code:
#include<stdio.h>
#include<conio.h>
int main()
{
int a,b,c;
float x;
}
[code]....
I need to write a program that accepts a number from the user, divides that number by two until it reaches one or cannot be divided evenly anymore, then adds all of the quotients from each division and displays them.
So something like this should be displayed:
Please enter a number: 8
8/2=4
4/2=2
2/2=1
4+2+1= 7
I thought about using an array to possibly store the quotients but I just can't see how that would work.
Whats the symbol for divide In C++
View 10 Replies View RelatedI am new to C programming and I am just wondering how to multiply / divide two different variables which the user type in as the promt is asking like this:
Code:
void inmatning3 (double *a, double *b) {
printf("Mata in tv217 stycken flyttal: "); /* asks you to type in 2 numbers */
scanf("%lf %lf", a, b);
}
When you've enterd the two numbers I need to eather multiply or divide the two variables "a" & "b" .....
Code:
#include <stdio.h> Code: #include <string.h>
int main() {
int i;
[Code]....
need to make triplet for the output
Code where the user wants to divide a number until it reaches to zero?
View 5 Replies View RelatedI need to make a program that takes in a user’s number and keep dividing it by 2 until it is 1.I need to display the division steps ...
I do not know how to keep making it divide by 2 until 1. I tired this but it obviously did not work..
Code:
#include <iostream>
using namespace std;
int main() {
//User Input
int input,total;
cout <<"Enter A Number To Be Divided By 2 Until 1" << endl << endl;
[Code] ....
I've been stuck on a divide a conquer algorithm problem for about an hour now, and I'm not sure how to solve it. I need to use divide-and-conquer to implement an algorithm that finds the dominant element of an array of positive integers and returns -1 if the array does not have a dominant element (a dominant element is one that occurs in more than half the elements of a given array).
No sorting may be used, and the only comparison that may be used is a test for equality.
I understand the general process I need to follow to solve this problem, but I'm not sure exactly how to convert my thoughts to code. I know that if a number x is the dominant element of an array A, the x must be the dominant element in either the first half of A, the second half of A, or both.
Here is what I have so far.
#include <iostream>
#include <string>
#include <vector>
using namespace std;
int find_dominant(int *A, int p, int r) {
[Code] ....
The program must run in O(n log n) time.
In this code nothing modify except function minMaxSearchRecursive
Code:
int min(int a, int b) {
if (a < b) {
return a;
} else {
return b;
[Code] .......
I am trying to do this:
Read a text file which is like:
2
2 10 1 2 7
3 8 3 7 7 10 7
The first line indicates how many paths exist in my design.
The second and third lines are those lines(the first number indicates 2 pairs, so 10,1 and 2,7 are 2 pairs)
The first element in the third line indicates 3 pairs and the pairs are 8,3 and 7,7 and 10,7.
I have been able to read the text file and store these into ONE array. However, I need to divide them up and have each line in a seperate array.
So for example
array alpha to contain 10,1 and 2,7
array beta to contain 8,3 and 7,7, and 10,7
How would you do this?
I want to multiply and divide 2 string that contains number. For example
s1=4 and s2=8 s1*s2=32 ,s2/s1=2
I don't want convert string to integer and do it.because i deal with big numbers.and these should be in string form.
I am trying to get a remainder of a number with a = 0.9144, rm = ry % a; however, I keep getting a divide by zero error (I believe due to the program rounding 0.9144 down to the integer 0).
View 2 Replies View RelatedQuestion about instead of using the division operator to display the output of user"s input....
View 4 Replies View RelatedI want to make a program to print the product of even numbers between 1 and 30 and sum of odd numbers between 1 and 30. But the answer of product is negative. The photo shows the output of the code.
#include <stdio.h>
#include <conio.h>
void main ()
{
int i, even_product=1, odd_sum=0;
for(i=1;i<=30;i++) // For loop starts here!
[Code]...
For example, to calculate GPA, we add all the grade point of a course and divide by the number of courses we are taking. How do I create a program in such a way that when the user enters grade point for two courses, it will add the grade points for the two course and divide by 2. And if another user enters grade points for six courses, it adds the grade points and divides by 6.
View 2 Replies View RelatedSo i have made an array and made a scanf in a for loop so it can store all numbers entered from keyboard in the array but i dont know how to put the numbers that are less than 5 in another array and then print that array out and the lenght of the array.
View 11 Replies View Related is there anyway to have a program where it ask for three numbers and you shows which which number is the largest and which is the smallest, e.g.
Enter 1st number: 30
Enter 2nd number: 10
Enter 3rd number: 30
Largest = 30
Smallest = 10
I am writing a program that prints the sum of even and odd numbers and here is my code
#include <iostream>
using namespace std;
const int SENTINEL = -999;
int main() {
int integers = 0;
int even = 0;
int odd = 0;
[Code] ....
Nut now in the output it adds -999 to the odd numbers ....
Q)Write a program to find the sum between (2 numbers )
what's the problem here !
#include<stdio.h>
main()
{
int a,b,c;
int sum=0;
for(a=0;b>a<c;a++)
{
printf(" number1=");
[Code]...
I have a homework assignment due that told me for the "input specification" that "n" is an integer greater then 0. How would I put this in and where?
View 1 Replies View RelatedWhen I go to run the Fibonacci function ( fib ), it begins to return incorrect calculations towards the higher numbers, but then seems to correct itself for a little bit, but then does it again and ultimately crashes. And the program seems to be crashing at random numbers. Sometimes the it will make it up to F(55), other times it will only get to F(20).
Also, when I go to run the program on a Linux server, it segfaults, but it doesn't when I just run it on my IDE. the function adds two arrays with individual digits together. It does this to allow the program to add numbers that would exceed the boundaries of INT_MAX.
Here is the header file "Fibonacci.h":
Code:
#ifndef __FIBONACCI_H
#define __FIBONACCI_H
typedef struct HugeInteger
{
// a dynamically allocated array to hold the digits of a huge integer
int *digits;
// the number of digits in the huge integer (approx. equal to array length)
int length;
} HugeInteger;
}
[code]....
#include <ctime>
#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
[Code] ....
Write a program that keeps generating two random numbers between 1 and 10 and asks the user for the product of the two numbers, e.g.: "What is 4 x 6?". If the user answers correctly, the program responds with "Right!"; otherwise, it displays: Wrong! 4 x 6 = 24.
Generate as many pairs of numbers as specified and get the answers from the user for each. If at any time, both numbers are the same as last time, generate two new numbers before asking for the answer. Continue generating 2 new numbers until at least one is different from last time.
After presenting the number of pairs of numbers specified and getting the answers, display how many the user got right; e.g.: You got 4 of 5 right. Then, ask if he or she wants to play again, like so: "Do you want to play again? [y/n]". If the user answers with 'y' or 'Y', it again reads the number of questions to ask and generates that many pairs of numbers and reads the answers like before. If the answer is n or N, it quits generating numbers. If the answer is anything but y, Y, n or N, it tells the user to enter one of those letters until it is.
When the user decides to quit and has got less than 75% of all the questions right, the program displays the multiplication table (1x1 through 10x10) before terminating.
After displaying the table, randomly generate two numbers between 1 and 10, display their product and first number and ask the user to guess the second as more practice. For example, the program will generate 7 and 9 and will display 63 and 7 and the user must guess the second number (i.e.: 9). Do this 3 times. Do not repeat code. Use a loop to do this 3 times.
Use a nested for loop to display the table; a bunch of cout statements will not be acceptable. You must also use a loop for any part that calls for repetition such as generating 5 pairs of numbers.
The following is a sample interaction between the user and the program:
Enter the number of questions to ask: 5
1. What is 3 x 9? 27
Right!
2. What is 2 x 7? 14
Right!
3. What is 8 x 9? 63
Wrong! 8 x 9 = 72
4. What is 6 x 3? 21
Wrong! 6 x 3 = 18
5. What is 2 x 9? 18
Right!
You got 3 out of 5 right which is 60%.
Play agian? [y/n] n
This is a program that display prime numbers from 1 to 100. it has problem linking when i run the program.
#include <iostream>
class Prime {
public:
int PrimeNo();
int Display();
};
// class Prime number
int Prime::PrimeNo()
[Code] ....