I am a beginner in C++. The program I want to create is as follows. The program will take a sentence as input from the user in italics and display it.
The output will be:
Enter a sentence :
Hello World!
You have entered : Hello World!
How to take user input in italics.
I am making program that allows the user to determine how big the array size will be and then asks the user to make up numbers to fill the array. Every time run the program on Dev C++ it says "program has stopped working"
Heres My Code:
//Assignment 19 Program 2
#include <iostream>
using namespace std;
int main()
[Code].....
In this simple end-of-chapter problem, the ages of two people are to be compared and determine who's older. The problem I'm experiencing is that the second user name input is being skipped and going straight to the second users age.
So while running the program it looks something like:
What is user ones name?
<input name>
How old are they?
<input age>
What is user twos name?
How old are they?
<input age>
<if statement result>
Here's my code:
Code: #include <iostream>
#include <string>
using namespace std;
int user_one_age;
int user_two_age;
string user_one_name;
string user_two_name;
[code].....
So I've got this form that a user puts in a numeric value into a text box. This value then has to be placed into a byte string of data so that it can be transmitted over as a packet. Bellow is what I have so far:
Code:
Byte[] OUTBuffer = new byte[65];//Allocate output memory buffer
Byte[] INBuffer = new byte[65]; //Allocate input memory buffer
if (setmSpeed == true)
{
OUTBuffer[0] = 0; //Not used, must be set to 0
OUTBuffer[1] = 0x85; //Command mode
[Code] ....
I've put in red the area where I'm having issues. I've tried different methods and have not been able to get this working yet. It only works if I speciffy the value manually as with OUTBuffer[1] = 0x85;, but I want byte 2 of OUTBuffer[] to be set with what I put in the text box.
I'm creating a program that should create a structure of a list of people entered by the user; the only problem I'm having is with the %c. When I have it, the loop only occurs once; if I put a %s, the loop occurs up to 25 times, but it doesn't write to the text file. Here is the code:
Code:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
[code]....
So im working with forks and creating 2 fork processes. One child and parent. What im trying to get the child to ask me for a value. Then the parent would start to figure out the value and keep trying. Once it figures it out its tells them you got it and simply stops the program. I cant seem to get the program to keep guessing and stop when the number is found which sends a sigint. Here's what i have so far.
Code:
#include <stdio.h>
#include <unistd.h>
#include <signal.h>
#include <stdbool.h>
int main() {
int j, i,pid;
[Code] .....
I have this code here that counts the number of alphabetic letters the user's input,the number of characters total, the number of words and the number of "the" that was used. However now I need to alter the user's input to have two spaces after the end of each period, no spaces between a word or comma and each sentence has to have a capitalized letter and display them at the end. And I'm stuck on the altering part. I briefly started the 2 spaces after each period but it won't display anything.
#include <cstring>
#include <iostream>
using namespace std;
int main ()
[code]....
I have written a program and i had to pass an array into a function and now i have a variable for the subscript of the array and i was the user to input data, specificlly a string, more specifically first and last name without having to create two arrays, i have to do this with other things in the program as well, here is part of the program:
int addFunc(const int totNum, string city[],string state[],string street[],string name[],
int addNum[],int zip[],int telNum[],double bal[],int dateLp[], int addCount, int accNum, int usNum)//function will add a new account {
int countAf = 1;
if (usNum < 20)
[Code] ....
it should be able to take firstname space lastname
I need to make a program that takes in a user’s number and keep dividing it by 2 until it is 1.I need to display the division steps ...
I do not know how to keep making it divide by 2 until 1. I tired this but it obviously did not work..
Code:
#include <iostream>
using namespace std;
int main() {
//User Input
int input,total;
cout <<"Enter A Number To Be Divided By 2 Until 1" << endl << endl;
[Code] ....
since around 2hours im really fighting with the cin command.It doesn't matter what exactly im trying, it's just not waiting for user input and keeps directly using 0 as "entered" value.
int Value;
cout << "Enter a new value: " << endl;
cin >> Value;
cout << "The value has been set to: " << Value;
I'm trying to make a simple program that accepts user input, simple stuff. When the user (me) enters a number to be sent to the console and i press enter so it accepts the data, it closes the command prompt and thus ending the program. I just need to find a key that i can use to continue but doesn't close cmd.
View 5 Replies View RelatedMy parameters are that the users input has to be from 1 to 9 and the same number can't be entered twice. How do i modify this code to make sure that the user did those things or an error message should appear that their input is invalid.
#include <iostream>
using namespace std;
int main() {
int square[3][3];
[Code] ......
Create a program that will ask the users name, age, and reddit username. have it tell them the information back, in the format: your name is (blank), you are (blank) years old, and your username is (blank).
So I started making my program
#include <stdio.h>
int main(int argc, char* argv[]) {
char name;
int age;
char username;
printf("Please input your name,your age,and reddit username");
scanf(" %c %d %c", &name, &age, &username);
printf(" %c %d %c", name, age, username);
return 0;
}
My program outputted H 0 and an upside down question mark. I was thinking that maybe the error in the program was that i was supposed to use %s instead of %c but im not entirely too sure.
how to see if what the user says is in the dictionary. I do not know what to put in ContainsKey() or after the information in console.writeline. I just want the user to type in the key then see if it is in the dictionary then print out the value if it is.
while ( Console.ReadLine() != "exit" )
{
Console.WriteLine("Type in word");
if (clothingDictionary.ContainsKey()== true)
{
Console.WriteLine("key is {0}, value is {1}", );
I am trying to get my input from user in the same line with certain width between but my output is not in the same line. my third variable which is fruit[i] is shown one line below . How I can fix this ?
#include <iostream>
using namespace std;
int main () {
int staff[3] , fruit[3];
[Code] ....
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]....
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is then how I could use that concept here.
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]...
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is I can't seem to really get that idea how I could use that concept here. I'm not really good with programming, fairly new at this.
I have a small loop that gets the user input, as well as acts as input validation to make sure he or she doesn't enter a value that is not within the specified range.
The user is supposed to enter a month number. E.g. if he or she chooses February, then enter 2, or December, 12.
It works correctly if they type a number that is not in the range, but goes into an infinite loop if, say, they type a string such as "month".
Code:
int main() {
// Variable Declaration(s)/Initialization(s)
int month=0;
// Get input
cout<<"Enter a month";
cin>>month;
[Code] ....
How could I go about revising this?
So I have a programming assignment which is for getting a user input in the format of m/d/yyyy. This is stored as d/m/yyyy. I have been able to code all the rest of the requirements of the program but the thing that is giving me trouble is this. The year is allowed to go from 1-3000. The format of the displayed date is:
a zero-filled, two-digit day number, a dash, full name of month, a dash, zero-filled, four-digit year.
I am able to use a switch statement in order to get my name of the month. What I am struggling to figure out is the whole zero filled two digit day and zero filled four digit year. From the way the input is store it appears to me that it will be stored as yyyy which means if you were to enter 0001 for year 1 then it should output it as that (this is an assumption based on format). What I don't get is that the day is entered and stored as d which means if you put in 12 how would it be stored. However if you put in 6 to print the output I would need to add a zero and I dont know how to do that either.
Here is the code for getting the input. The function must stay formated this way as per the instructor. The / is stored but ignored hence the char for second and fourth since / is a char
Code:
void getDate (int& day, int& month, int& year){
char second;
char fourth;
cout << "Please enter a date in the format of m/d/yyyy" << endl;
cin >> month >> second >> day >>fourth >> year;
}
How can I write my simple program so if the user enters an invalid number, The program won’t exit? I know I am supposed to use a if (cin) or if (!cin),
But I don’t know where in the program or how I should use it. Right now my Program looks kind of like this:
If (number > 1 && number < 1001)
Go through some function loops
Else
Cout << “invalid number”;
I need to write it so when the user enters an invalid number, the program would Keep asking for the right number until it's given.
I tried to scanf the input by the user into the function but it does not read my input. Read on one of the thread, it said that to scanf a input into a double, need to use %1f instead to %d (which normally used. I tried changing it to %1f and it still did not work.
Code:
#include <stdio.h>
#include <math.h>
/* function main begins program execution */
int main( void )
{
double amount; /* amount on deposit */
[Code] ....
Firstly, I'd like to say that I'm relatively new to functions and my course standards state that I'm now supposed to relay information from the user to the program via functions, this means that I'm no longer able to use 'printf/scanf' combos in the main function.
Is it possible to do it via functions? I've tried the following method for example, but to no avail.
Code:
#include <stdio.h>
int getlowR();
int main(void)
{
getlowR();
[Code] ....
I think the following works but then lowRange is native to the function, isn't it? How can I use it outside the function? For example, how would I go about actually printing the value acquired by the function in main?
Now i got here a program that asks the user to input 2 numbers if the first inputed number is smaller than the second then show all even numbers from the range of the 1st inputed number till the 2nd inputed number, but if the first inputed number is greater than the second then display all odd numbers from the range of the 1st number till the 2nd.
now my question is how do i invert the odd numbers?(on the 2nd condition)
Code:
#include<stdio.h>
int main(void) {
int i,a,b,x;
printf("Enter two numbers");
printf("
First number:");
[Code] ......
For the following program, I'd like to make sure the user input is between 1 and 40 characters. To do this, how would I complete the if statement below?
Code:
char p_input[41];
printf("Enter a name (1-40 characters):");
fgets(p_input, 41, stdin);
if (p_input ....??
I want to create three files whose names are same but extensions are different. I have to take the name from user. I tried following code but it didn't worked ...
Code:
printf("Name of the file:"); scanf("%s",name);
printf("Format of Input file:");
scanf("%s",ext);
f1=fopen(name.ext,"r");
f2=fopen(name.dat,"w");
f3=fopen(name.src,"w");
f4=fopen(name.RMH,"w");
This is a function that calculates factorials of the user input.I'm not getting a favorable printf result.
Code:
void calcFactorial ()
{
int arr [100];
int num = 0;
int i;
int factorials = 0;
int product = 1;
}
[code].....
