I'm trying to return a short int in a function..This is my function signature :
short int* StartRecord(int seconds)
this is my array :
short int waveIn[NUMPTS];
I'm trying to get the data into an array :
short int arr [] = StartRecord(3);
getting this error: Error2error C2440: 'initializing' : cannot convert from 'short *' to 'short []'
I need to create a function which will print a list from 100Hz to 1000Hz then 1000Hz to 9000Hz. I have created a function in order to calculate and set up the frequency values from 100Hz to 9000Hz using two for loops as shown below. However I am unsure how to return this to the array at the main.
int main(void) {
double Frequency[18];
system ("PAUSE");
return(0); } double Frequency (void)
{
int count;
[Code]....
I am trying to neaten my code by putting them in different cpp files but in one function an array is changed:
int function(int array2[100][9])
{
for (int i =0; i < 100; i++)
[Code]....
I'm having trouble returning a char array by a function, here's the code. The problem is the 'reverse' function, the purpose of the function is to send two char arrays, 'newline' containing the char array, reverse it and place it in the 'rev' char array then output it back in main, however the output remains blank so I assume there must be something wrong with the reverse function.
Code:
#include <stdio.h>
#define MAXLINE 10
int fgetline(char line[], int maxline);
void copy(char to[], char from[]);
void reverse(char forw[], char rev[], int arrsize);
[Code] .....
I know how to pass a 2-D array to a function. The prototype for that is void f(int (*p)[2]) assuming the array is of integers and there are 2 columns in it.
However, if I wanted the same function to return a pointer to a 2-D array, what would be the prototype?
I have been trying to make a function that compares all the values of the array and if they are all equal will return a value to print true. The problem I am having is that regardless of what values I enter the function is always returning true. Any way to tell the program o check all the values in one command instead I put them each,
Code:
#include<stdio.h>
#include<stdlib.h>
int compare(int arrayA[], int arrayB[]);
[Code]....
How can I return a dynamically allocated 2d array from a function? Do I use like this:
int main(){
char **array;
array=func();
} char ** func(){
char** ptr=new char[5]; //five words
ptr[0]=new char[size of word1];
*ptr[0]=word1
........
return ptr;
}
This a very simple program I created because I dont understand how do this. My goal is to be able to use the pointer *s5 throughout the program. For example I would to like to call other functions and pass that pointer through the function. I understand the dynamic allocation and pointers for the most part but Im confused here because the "new char[20]" variable will die after the function and I dont want it to.
#include <iostream>
#include <cstdlib>
#include <cstring>
using namespace std;
void testArray ( char *s5 );
int main ( int argc, char *argv[] )
[Code] .....
Also does strlen count the null terminator?
I want to return a char array to the main() function, but its returning garbage value.
#include<stdio.h>
//#include<conio.h>
#include<string.h>
char* strtrmm();
int main() {
char str1[100],c1[100];
[Code] .....
I'm having trouble reading a block of bytes into a vector of short ints. My code is as follows:
Code:
FileStream.seekg(2821);
vector<short> g_Data;
int iter = 0;
g_Data.reserve(maxNumOfInts);
[Code] ....
The relevant block of data starts at offset 2821 in the file. Every two bytes are a signed short integer. What's odd is that it's giving me the correct results only part of the time. At offset 1052421 and 1052422 there are two bytes 40 and 1F that are correctly read in as 8000, but at offset 1052415 and 1052416 bytes 88 and 13 are read in as -120 instead of 5000.
I don't see anything wrong with my code, though, unless I'm misunderstanding completely how to convert an array of two bytes into a single float. Is my method correct? Better still, is there some way to just convert en mass an array of bytes into a vector of signed short ints?
Any function of simply converting character array to a short int?For example. char array[4]={'0','2','f','f'}; to short int 767?
View 3 Replies View RelatedHow can i write a function that will read an "unsigned integer" into a variable of type "unsigned short int"? i can not use cin >> inside the function.. so i am looking for atleast a hint!
View 16 Replies View RelatedI am making a game commonly know as the Hangman using C++.
Now I am trying to add a man in it like this:
0
|/
|
/
Now the problem i am facing is that i am using a check that if a function returns the value 0 "return 0" it means the guess is wrong and it will not update the man but if it returns any value there will be a function called which will update the man.
I just wanna know that how i am going to use the check, the kind of thing that i am trying to use is, in general words "if(function returns a value) then update the man"
int main() {
return match;
}
How are we going to use it in check that if int main is returning 'match' in the check...
This simple little program is not returning a value. The output is
" (string) contains characters" (The number of characters is supposed to display between the 'contains' and 'characters.'
However, if I go to the function and cout the length, the cout in the main body displays just fine.
Here's the main portion :
cout << "'" << input << "' contains "; //Output of character count.
charCount(input);
cout << " characters, including any spaces.
"; //Output of character count.
and here's the function.
int charCount(char *string) {
int length = 0; //Variable to hold the number of characters.
//Gets the number of characters contained in *string and puts that number into length.
[Code] .....
As the title says, i'm using a function which returns a pointer to a struct:
the struct is the following:
Code:
typedef struct POINT
{
uint16_t x;
uint16_t y;
}
Coordinate; the function i'm using:
Code:
Coordinate * Read_XTP2046(void)
{static Coordinate screen;
//calculations to determine the coordinates
screen.x=(temp[1]+temp[2])/2;
screen.y=(temp[0]+temp[2])/2;
// and so on...
return &screen;}
The question is: how do i catch this pointer and make it into a Coordinate struct in which i can read the x and y.
In my main program i would do the following:
Code:
Coordinate cor;
cor = Read_XTP2046();
This does not work, as the function returns a pointer, but how to transform this pointer into a Coordinate struct.
Here's a small portion of my program:
Code:
int choice(void) {
char buffer[BUFSIZ];
char answer;
printf("
[Code] .....
I am wondering which is correct to use
Code: return choice();
or
Code: choice();
return num;
I am using two threads and i want to take value of a function from one thread and use it in other. I am not good at the concepts of threads. Here is the following code:
Code:
void ThreadA(void const *argument){
uint32_t status = I2S002_FAIL;
status = I2S002_Config(&I2S002_Handle0, &I2SConfig_U0C1_A);
if (status != DAVEApp_SUCCESS) {
[Code] ....
So, i want to use the return value of temp_buffer from ThreadB into Thread C and want to put this value to TXBuf in ThreadA...
why the function is not returning the integer 1 or 0 ... We have two arrays A and B, each of 10 integers. Write a function that tests if every element of array A is equal to its corresponding element in array B. The function is to return true (1) if all elements are equal and false (0) if at least one element is not equal.*/
#include <stdio.h>
#include <iostream>
#include <time.h>
using namespace std;
int TEST (int arrayA[], int arrayB[], int j);
int main() {
srand (time(NULL));
[code].....
How is the definition of the term "expression" affected by value returning functions, and why?
View 5 Replies View RelatedIs this considered a memory leak?
Polygon* create_square(const Vector2d& position, const RGB& colour, const std::string name) {
// Polygon, Vector2D, RPG and Vertex2d are structs with public data members only
Polygon *temp = new Polygon;
temp->name = name;
temp->colour = colour;
temp->position = position;
temp->vertices = new Vertex2d;
return temp;
}
#include<iostream>
using namespace std;
int &fun() {
int x = 10;
return x;
}
int main() {
fun() = 30;
cout << fun();
return 0;
}
The code outputs 10.
Shouldn't it show an error because x is created locally on stack and gets destroyed on function return?
#include <stdio.h>
#include <conio.h>
#include <string.h>
[Code].....
The code above is my attempt. If I can get the above code to work
I have a function, which has to return some int data. In that function there are multiple return statements. There is also possibility that function may return in some cases. Will this result in undefined behavior???
View 3 Replies View RelatedI am writing a function to take two vectors and put them end to end in a third vector. I'm new to working with vectors, and I cannot figure out why my append function is not returning vector C. I had the function print out vector C within it to make sure the logic in the function wasn't the problem, and it worked perfectly. My code is as follows:
#include <iostream>
#include <vector>
using namespace std;
//append function to put vector b after vector a in vector c
vector <int> append(vector <int> a, vector <int> B)/>/>/> {
vector <int> c;
[code]....
and my output is as follows:
Vector A contains: 10 18 123 172
Vector B contains: 283 117 17
The two vectors back to back are:
Obviously, the third vector is not returning from the function to main properly, but why.
I'm trying to solve some problems in c that i read in internet as the following example.
Make a program who receives a int number n>0 and returns how many digits of n, and the first digit of n.
I have a bool type function and set it to explicitly return false, but I am still getting true as the return.
#include <iostream>
#include <fstream>
using namespace std;
int main(int argc, char* argv[]){
double coeffs[3];
double roots[2];
[code].....
