I have a hit a snag in a number guessing game program. I was given a half-completed program and told to use functions to complete the missing pieces. It looks unwieldy, but this is how it is supposed to be. I have temporarily made the random guess value visible for troubleshooting purposes.
#include <iostream> #include <time.h> #include <stdlib.h> using namespace std; int welcome() { cout << " Welcome to the hi-low game!" << endl;
[code]....
The issue lies within this piece of code:
checkGuess(guess, correct); done = false; //either true or false } while (!done); cout << "Congratulations, you got it!" << endl; return 0; }
I need to manipulate the Boolean variable done so that it registers as false when the user inputs a number higher or lower than the randomly selected value. However, if the user guesses correctly, done will become true and the program will end.
As it stands now, the program will not terminate, and if I set done equal to true like so:
checkGuess(guess, correct); done = true; //either true or false } while (!done); cout << "Congratulations, you got it!" << endl; return 0; }
Every number the user inputs will register as correct instead of the one right guess.
I'm havin trouble outputing different false statements in a boolean function... I'm currently working on a "secret number game" program which must generate a secret number and inform the user if his/her guess number is to high, to low or correct. I know boolean return true and false.. If the number is correct, the true statement will appear, if false... THAT'S where my problem starts cause now I have TWO statements to output..In a Function.. How do I make my program able to tell if the number guessed is "too high" or "too low" ?
i have a Boolean function containing 2D dynamic array, it'll retain either 0 or 1, how can i delete the dynamic array?
bool something (int** a,int b, int c) { int **arr = new int*[b]; for(int i=0;i<b;i++) arr[i]= new int[c]; if (...) return 0; else ... if (...) return 0; }
My constant vector list is { 'a', 'e', 'i', 'o', 'u', 'y'}. My error comes in on line 20. I am not calling the boolean correctly. If I type in the letter "i". Then the function should output 2 since i is in the 2nd index spot of my vector list. How to fix my error? I am not understanding why my line of code is not working.
I was instructed to write a binary search function which would return true if an element, inputted by the user, was found in the array, and false if it was not. I'm not sure why, but my function always returns false. My code is as follows.
#include <iostream> #include <cstdlib> #include <ctime> using namespace std; //binary search function bool search (int array[], int item)
I don't know that a Function is the right word for switch/case but it seems like this would exist, is there a way to test multiple booleans using a switch function?
I am making a game commonly know as the Hangman using C++.
Now I am trying to add a man in it like this:
0 |/ | /
Now the problem i am facing is that i am using a check that if a function returns the value 0 "return 0" it means the guess is wrong and it will not update the man but if it returns any value there will be a function called which will update the man.
I just wanna know that how i am going to use the check, the kind of thing that i am trying to use is, in general words "if(function returns a value) then update the man"
int main() { return match; }
How are we going to use it in check that if int main is returning 'match' in the check...
This simple little program is not returning a value. The output is
" (string) contains characters" (The number of characters is supposed to display between the 'contains' and 'characters.'
However, if I go to the function and cout the length, the cout in the main body displays just fine.
Here's the main portion :
cout << "'" << input << "' contains "; //Output of character count. charCount(input); cout << " characters, including any spaces. "; //Output of character count.
and here's the function.
int charCount(char *string) { int length = 0; //Variable to hold the number of characters. //Gets the number of characters contained in *string and puts that number into length.
As the title says, i'm using a function which returns a pointer to a struct:
the struct is the following:
Code: typedef struct POINT { uint16_t x; uint16_t y; }
Coordinate; the function i'm using:
Code: Coordinate * Read_XTP2046(void) {static Coordinate screen; //calculations to determine the coordinates screen.x=(temp[1]+temp[2])/2; screen.y=(temp[0]+temp[2])/2; // and so on... return &screen;}
The question is: how do i catch this pointer and make it into a Coordinate struct in which i can read the x and y.
In my main program i would do the following:
Code: Coordinate cor; cor = Read_XTP2046();
This does not work, as the function returns a pointer, but how to transform this pointer into a Coordinate struct.
I need to create a function which will print a list from 100Hz to 1000Hz then 1000Hz to 9000Hz. I have created a function in order to calculate and set up the frequency values from 100Hz to 9000Hz using two for loops as shown below. However I am unsure how to return this to the array at the main.
int main(void) { double Frequency[18]; system ("PAUSE"); return(0); } double Frequency (void) { int count;
I am using two threads and i want to take value of a function from one thread and use it in other. I am not good at the concepts of threads. Here is the following code:
Code: void ThreadA(void const *argument){ uint32_t status = I2S002_FAIL;
status = I2S002_Config(&I2S002_Handle0, &I2SConfig_U0C1_A); if (status != DAVEApp_SUCCESS) {
[Code] ....
So, i want to use the return value of temp_buffer from ThreadB into Thread C and want to put this value to TXBuf in ThreadA...
why the function is not returning the integer 1 or 0 ... We have two arrays A and B, each of 10 integers. Write a function that tests if every element of array A is equal to its corresponding element in array B. The function is to return true (1) if all elements are equal and false (0) if at least one element is not equal.*/
#include <stdio.h> #include <iostream> #include <time.h> using namespace std; int TEST (int arrayA[], int arrayB[], int j); int main() { srand (time(NULL));
Polygon* create_square(const Vector2d& position, const RGB& colour, const std::string name) { // Polygon, Vector2D, RPG and Vertex2d are structs with public data members only Polygon *temp = new Polygon; temp->name = name; temp->colour = colour; temp->position = position; temp->vertices = new Vertex2d; return temp; }
I have a function, which has to return some int data. In that function there are multiple return statements. There is also possibility that function may return in some cases. Will this result in undefined behavior???
I am writing a function to take two vectors and put them end to end in a third vector. I'm new to working with vectors, and I cannot figure out why my append function is not returning vector C. I had the function print out vector C within it to make sure the logic in the function wasn't the problem, and it worked perfectly. My code is as follows:
#include <iostream> #include <vector> using namespace std; //append function to put vector b after vector a in vector c vector <int> append(vector <int> a, vector <int> B)/>/>/> { vector <int> c;
[code]....
and my output is as follows:
Vector A contains: 10 18 123 172 Vector B contains: 283 117 17
The two vectors back to back are:
Obviously, the third vector is not returning from the function to main properly, but why.