I'm trying to write a program that uses the Boost library to input a string date in the format mm/dd/year and outputs to the string its corresponding day of the week. I wrote the program that I thought would accomplish this, but it doesn't seem to work. Below is the code I wrote:
When I compile this using codeblocks it gives me the error "In function `ZN5boost9date_time19month_str_to_ushortINS_9gregorian10greg_monthEEEtRKSs':| C:Users osaDesktop est3........Liboost_1_55_0oostdate_timedate_parsing.hpp|67|undefined reference to `boost::gregorian::greg_month::get_month_map_ptr()'". And it takes me to the file date_parsing.hpp and highlights line 67. I don't understand why this isn't working.
I can access a physical device to read a specific sector in a USB hard drive. But my question is how can I Write to a specific sector? Lets say I want to replace what is in a specific sector of a hard drive with a new data.
I'm trying to write a program that has a menu with a switch statement. I'm getting "case label'1' not within a switch statement" and subsequent errors for the other two choices and the default.
int main(){ int choice; Matrix A,B,C; cout <<"What would you like to do? "<< endl;
i'm making a program that, given a person's birthdate or any other date, will display the day of the week of the person was born.
There is this part where it says "use a switch statement to make this calculation, If desired month is 12, add the number of days for November, if desired month is 11 add the number of days for october....
So it's suppose to start with "case 12 :...
I can't figure out what to write for the statement....
I have two date/time structures which I'm populating, but when I populate the second one it sets the same values in the first. This is what I've got so far
Currently I am working on a program where you enter in a date 14 03 2013 (Day, Month, Year) and you get the next day. I seem to be coming stuck with months with less than 31 days, and the whole leap year thing. Here is my code so far.
Code: #include <stdio.h> int day, month, year, next_day, next_month, next_year, calculation; int main() { printf("Enter a date in the form day/month/year: "); scanf("%d %d %d", &day, &month, &year);
If I am asked to declare a data type for Date which should be in the format DD/MM/YY, which data type should i use for it? Is there any data type known as Date in C?
How can I check for an invalid date when I run the program? I am trying to enter a conditional statement that checks for a valid or invalid date.
Programing Question: Write a program that inputs a date (e.g., July 4, 2008) and outputs the day of the week that corresponds to that date. Here is what I Have. The program runs. I need it to loop around.
#include <iostream> using namespace std; const int JANUARY = 1; const int FEBRUARY = 2; const int MARCH = 3; const int APRIL = 4;
I'm doing a daily time record that record every inputed date on a txt file how will have an option or how will I delete a some of the choosen date? i'm using C++
So I have a programming assignment which is for getting a user input in the format of m/d/yyyy. This is stored as d/m/yyyy. I have been able to code all the rest of the requirements of the program but the thing that is giving me trouble is this. The year is allowed to go from 1-3000. The format of the displayed date is:
a zero-filled, two-digit day number, a dash, full name of month, a dash, zero-filled, four-digit year.
I am able to use a switch statement in order to get my name of the month. What I am struggling to figure out is the whole zero filled two digit day and zero filled four digit year. From the way the input is store it appears to me that it will be stored as yyyy which means if you were to enter 0001 for year 1 then it should output it as that (this is an assumption based on format). What I don't get is that the day is entered and stored as d which means if you put in 12 how would it be stored. However if you put in 6 to print the output I would need to add a zero and I dont know how to do that either.
Here is the code for getting the input. The function must stay formated this way as per the instructor. The / is stored but ignored hence the char for second and fourth since / is a char
Code: void getDate (int& day, int& month, int& year){ char second; char fourth; cout << "Please enter a date in the format of m/d/yyyy" << endl; cin >> month >> second >> day >>fourth >> year; }
Is there any way to do date math using standard C libraries? I looked around in the time.h but didn't see what I needed.
What I need to do is be able to add a certain number of minutes to a date and have it give the current date/time. For example, add 15918765 minutes to 01/01/1980 00:00 and have it tell me 04/07/2010 4:45PM. I really don't want to write this myself or go platform-specific.
I am building a template for CodeBlocks, which pre-write some includes, the main skull and a header.
This header looks like that : /** * @Author Me * @Description Brief description * @Date ?? */
I would like to put the current Date, just after the line @Date, is-it possible ? And if yes, it-is possible to put a field @FileName which copy the filename into the comment ?
Program to convert a date entered into roman numerals. I can only use one output prompt to get the date, so that makes it more difficult. Here is what i have, but how to go about the rest of it.
#include <cstdlib> #include <iostream> #include <string> using namespace std; int array_date[20]; char I; // one
i have a form in which i have a field date of birth , and a textbox to fill date of birth , when a person fills his date of birth like 01/01/1990 , then it will be saved into database , and when i retrieve this date form database then this comes 01/01/1990 12:00 AM , i want only date part from it.