C :: Converting To Lowercase And Counting Words

Apr 12, 2014

I am writing a program when the beginning it you have to pick which step to preform out of a few steps. Once you choose the step. The user is asked to input what is asked and it should preform it. I have completed most of my steps but the one step giving me a hard time is converting a user inputed sentence into all lowercase letters, and then count the words of it. My program starts out like this if you pick this step Code: else

if (choice == 3) {
/* Gather user's input */
printf("
You have chosen to convert a sentence to all lowercase letters and count the words
"
"Enter the sentence: ");
gets ( sentence );

Call the function to convert the whole sentence to lowercase and count the number of words */

lowercase_string ( &sentence);
countSentence ( &sentence);
} /* End if statement */

this is the easy part in which I presume I did correctly, but now this is where I am getting the problems:

/* Prompts user to enter a sentence and convert it to lowercase and count the number of words */

void
countSentence (char *sentence)
void
lowercase_string (char*)
{
[code]....

I want to output the original sentence, then the sentence with all lower case letters, then at last output the number of words in the sentence. I declared all my variables up top, and I am wondering where my mistake is. When trying to compile it, I only get syntax errors which I don't understand.

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how to convert a string containing Uppercase/Lowercase/Whitespace/Special Characters to only Lowercase and removing the whitespace and characters.

For example, a message like:

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Change that message to:

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Code:

#include <stdio.h>
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[Code].....

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This code is compile but must have some upgrades :

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Code:
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[Code] .....

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Code: /*
*
*
*
* Usage:
*
* ./countWord <path>
*/

#define _XOPEN_SOURCE 700
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[Code] ....

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Code:

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int main(){
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[Code] ...

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Code:

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[code]....

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[Code] ....

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[Code] .....

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[Code].....

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[Code]...

This is the output I receive:

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Code:
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