C/C++ :: Odd Numbers Divisible By N
Apr 28, 2012How to write a program of odd numbers divisible by n
View 1 RepliesHow to write a program of odd numbers divisible by n
View 1 RepliesI've pretty much finished the entire program, except for the actual calculation part.
"Given a range of values determine how many integers within that range, including the end points, are multiples of a third value entered by the user. The user should be permitted to enter as many of these third values as desired and your output will be the sum of total multiples found."
I've defined functions to take user input for the low range, high range and a do-while loop to take as many third inputs as the user wants (terminated by entering -1, as requested by the question)
To actually calculate if they're divisible, I found out that if A%B = 0, then they are divisible, so I thought I would create a loop where each value in the range between A and B is checked against the third value to see if they output a zero.
What I need to end up with is a program that tells the user how many integers are divisible by the numbers in the range, i.e: "Enter the low range value: 335 Enter the high range value: 475 Enter a value to check within the range: 17 Enter a value to check within the range: -1 There are 8 total values that are divisible by the numbers in the range." Going back to my original question, how would I create a loop or something to "check" how many values are equal to zero, and consequently increment a variable for each instance? (This is how I think it should be done)
Code:
#include <stdio.h>
//GLOBAL DECLARATIONS
int getlowR();
int gethighR(int);
[Code].....
A program that outputs all numbers divisible by both 5 and 6.This is what i have written :
#include<stdio.h>
int main () {
int i=200;
int b=10;
while(i<1000)
i b/6%==0
}
where could i have gone wrong.
Code:
#include <stdio.h>
int main(){
int A, B;
char decision;
printf("Do you have an integer to input? [Y/N]: ");
scanf("%c",&decision);
if(decision=='Y' || decision=='y'){
[Code]....
After entering a single integer, it doesn't scan again for another integer. What's wrong?
I'm using a mac btw, if that makes a difference with Ubuntu/Linux.
Does this program solve the problem of testing an integer to be divisible by 6?
Code:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Chapter7Problem5
[Code] ....
Write a program that displays all the numbers from 100 to 1,000, ten per line, that are divisible by 5 and 6. Numbers are separated by exactly one space.
#include <iostream>
#include <stdlib.h>
using namespace std;
[Code]....
#include <iostream>
using namespace std;
int main() {
int i=0;
while (i<=100) {
[Code] .....
the part where i need to check for values divisible by 5 is incomplete.
Assume you want to make sure that the user enters a positive number that is divisible by 10 with no remainder. Write the condition you would use in the following do-while loop.
do {
cout << “Enter a positive number that is divisible by 10 with no remainder” << endl;
cin >> number;
}
while ( ____________________________________________________________);
How to do the problem below using loop?
Input numbers until the user types a 0, then output the product of the non 0 numbers: e
E.g., if the user types 2 4 6 0, the program should output 48
User enters sentence "The Smiths have two daughters, three sons, two cats and one dog." (The numbers may change depending on what the user chooses to enter. He told us the range would be from zero to nine.) and we have to convert the written numbers within the sentence into actual decimal numbers and print out the new sentence. Ex. The Smiths have 2 daughters, 3 sons...etc.
I have written the following bit of code which reads the string and finds all the "written numbers" but I am not sure how to proceed from there. I am stuck on how to print out the new sentence with the converted numbers as my professor mentioned something about creating the new string using dynamic memory allocation.
Code:
#include <stdio.h>#include <string.h>
int main () {
char A[100];
int length = 0;
int i;
[Code] .....
Find all the prime numbers between a given pair of numbers. Numbers should be read in from an input file called "numbers.txt" and find all the prime numbers between them. Store the prime numbers in an array, then sort the array from greatest to least. Display the array before and after the sort.
I'm stuck on how to put the prime numbers into an array.
The input file has the numbers 1 & 100.
Here's what I have so far.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
ifstream fin;
fin.open("numbers.txt");
[Code] .....
Question: How to find a duplicate numbers and numbers found once in array.
View 7 Replies View RelatedI'm working on this program that I have to design a class Numbers that can be used to translate whole numbers to the English description of the number.
Now this is what I got so far:
#include <iostream>
#include <string>
using namespace std;
class Numbers {
private:
int number;
static string ones[];
static string tens[];
[Code] ....
The program seems to work. However its not giving me the right number description,
Example:
Please enter the amount you would like translated into words: 5
six dollars
please enter another number: 10
eleven dollars
please enter another number: 20
thirty dollars
please enter another number: 30
forty dollars
please enter another number: 100
two hundred dollars
please enter another number: 150
two hundred sixty dollars
please enter another number: 500
six hundred dollars
please enter another number: 1000
two thousand dollars
please enter another number:
ignoring negative numbers when I am trying to add up only positive numbers.
SAMPLE:
if (num>=0) {
sum= sum + num;
}
else
how would the else in this case being a negative number not be included in the sum
I need a list generated of all possible subset combinations for the set 1,2,3,4,5,6,7,8,9,10,12. Select six. Numbers cannot repeat.
Example subset: 1,2,3,4,5,6 (six selected, no repeats).
Example of what I dont need: 1,1,2,2,3,3,4,4,5,5,12,12 or 1,1,1,1,1,6.
I will also need the opposites removed, meaning...if I have 1,3,5,7,9,11 then I need 2,4,6,8,10,12 eliminated from the final list.
This is for a game, where you must select all numbers right or no numbers right.
The code below will generate combinations of numbers from 1 to 25 in an 15 numbers array. The only filter I've applied is that the sum of all the numbers in the vectors divided by 15 needs to be between 13 and 14.
I would like to count how many consecutive numbers there are in one combination, so that later i can apply another filter.. for example:
1 3 4 5 6 8 10 13 14 16 17 18 19 20 25
3 + 4 = 1
4 + 5 = 1
5 + 6 = 1
13 + 14 = 1
16 + 17 = 1
17 + 18 = 1
18 + 19 = 1
19 + 20 = 1
_____________
Count = 8, in this case..
I think it's not very difficult to do, but i just can't see how to do it.
#include <iostream>
#include <vector>
#include <numeric>
[Code]....
I want to make a program to print the product of even numbers between 1 and 30 and sum of odd numbers between 1 and 30. But the answer of product is negative. The photo shows the output of the code.
#include <stdio.h>
#include <conio.h>
void main ()
{
int i, even_product=1, odd_sum=0;
for(i=1;i<=30;i++) // For loop starts here!
[Code]...
So i have made an array and made a scanf in a for loop so it can store all numbers entered from keyboard in the array but i dont know how to put the numbers that are less than 5 in another array and then print that array out and the lenght of the array.
View 11 Replies View RelatedI wrote a program which sends a starting and ending range to other processes and the processes calculate the prime numbers in that range and return the count of prime numbers to the head process, process 0. But this is not working properly at the moment. I realize I still have to split up the range based on how many processes I have...I still have not figured out how I want to set that up. I
Code:
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
int isPrime(int num);
int main(int argc, char **argv){
}
[code]....
Write a program which reads a stream of numbers from a file, and writes only the positive numbers to a second file. The user should be prompted to enter the names of both the input file and output file in main(), and then main() will open both files. Another function named process() must then be called to read all the numbers from the input file and write the positive numbers to the output file. Note that you must pass the open stream variables for each file as arguments to the process() function, and that you need to (always) double check that the files opened successfully before using them.
This is what I have so far but its not working out!
#include <iostream>
#include <fstream>
#include <stdlib.h>
using namespace std;
int process(ifstream &inf, ofstream &outf);
[Code] ....
All Numbers are random.
This will be the output
Enter Number: 4
Enter Number: 3
Enter Number: 2
Enter Number: 1
Enter Number 6
The Sum of all even numbers is: 12
The Sum of all odd numbers is 4
i have trouble with comparing two of the biggest numbers out of four numbers. Im working on an assigment with a dice game where i need to tell the computer the following;
"if the biggest number out of dice_three and dice_four is the same number as the biggest of dice_two and dice_one, then loop1=true"
this is how i have been writing it so far ;
if
(MAXA(dice_three,dice_four) == MAX(dice_two,dice_one)){
lopp 1=true;
}
(as seen) i am using:
#define MAX(dice_one,dice_two) ( (dice_one) > (dice_two) ? (dice_one) : (dice_two) )
#define MAXA(dice_three,dice_four) ( (dice_three) > (dice_four) ? (dice_three) : (dice_four) )
to calculate which one is the biggest number out of the two pares. The code i have been writing so far seem to have the wrong syntax.
If I have the number 88 how would I add 00 to the end of and turn it into 8800? Bitwise shifts is the only way I can think of to do this but it doesn't work. It completely changes the numbers.
View 6 Replies View RelatedDesign an algorithm using flowchart to prompt the user for 5 values. Total up all these values and print the total at the end of the program. If the number is equal to zero the system will terminate.
View 5 Replies View Related is there anyway to have a program where it ask for three numbers and you shows which which number is the largest and which is the smallest, e.g.
Enter 1st number: 30
Enter 2nd number: 10
Enter 3rd number: 30
Largest = 30
Smallest = 10
Code:
#include<stdio.h>
int main(){
int num,i,count,min,max,sum=0;
printf("Enter min range: ");
scanf("%d",&min);
[code]....
when I ran the program , I got "4" with prime numbers. I only way I was able to remove the "4" was this "num!=4".