I print the original list, then reverse it, then try to print it again. Here is what I get when I do that:
So that second line should print 2 1 4 5
Here is the reverse function:
void reverseCirListDeque(struct cirListDeque *q)
{
struct DLink *curr = q->Sentinel;
do{
[Code].....
When I run this in main it gives me a windows error message. I believe it has something to do with my insertAtEnd function but I've gone over it a million times....
#include<iostream>
#include<string>
#include<vector>
#include"RhymeGame.h"
using namespace std;
Game::Game() {
head = NULL;
[Code] ....
Should my if statement be
if (tail== NULL) or if(tail->next == tail) ?
I have a function that I would like to add to tail. It is not correct.
template<class T>
void DoublyLinkedCircularList<T> :: addToTail(T element) {
DoublyLinkedNode<T>* head;
DoublyLinkedNode<T>* temp;
temp->element = element;
[Code] .....
How do I fix it?
When compiling the source I get the following error
"pms_program.h:54:56: error: expected declaration specifiers or ‘...’ before ‘CourseType’"
the code you are looking for in pms_course.h ( there is a circular dependency between pms.h , pms_course.h and pms_program.h)
function prototype AppendProgram ( part of doubly linked list )
I have attached the full course code.
As much as I like I cannot change the structure of the startup code ...
please see attached zip file for the entire source code.
Code is:
#include<stdio.h>
struct node {
int info;
struct node *next,*prev;
[Code] ....
How to reverse a linked list .....
I was trying to reverse a linklist in reverse direction using the recursion. I was able to reverse n - 1 element but it is not printing the first one. Below is my code.
Code:
typedef struct linklist {
int data;
linklist *next;
};
void add(int data,linklist **node) {
[code]....
This is happening since recursion is starting from second node, which is due to reason not printing the first one when recursion print values from stack once
node != NULL
Condition is met.
Currently I am using below statement for printing the first element;
reverse_recur(node);
printf("
Print In Reverse Order
%d
",node->data);
I've been making a circular linked list and I'm trying to assign each list a "name" and its next "link" but when I run my code it crashes.
Soldier *Head;
Head = NULL;
string names[] = {"Arman","Bogut","Castro","Damascus","Elene"};
for (int i = 0; i < 5; ++i) {
[Code] .....
The code below is for reversing every k nodes of the linked list. While running the Program it crashes.
Code:
#include<stdio.h>
#include<stdlib.h>
struct node {
int info;
struct node *next;
[Code] ....
Why is it sufficient to only have a pointer to the last node of the list?
View 3 Replies View RelatedI need to make the functions using these function prototypes. I am mainly having problems with GetFirst() and SwapData() but how to do it..
Header File with Prototypes
Code:
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
/**
* @file
* This file provided a doubly-linked list implementation capable of storing any arbitrary data.
* The list implementation relies on a chain metaphor: a list is merely a sequence of links
* (ListItems) and there is no separate construct to represent the entire list, each ListItem in it
[Code]....
namespace main_savitch_5 {
class polynode {
public:
// CONSTRUCTOR: Creates a node containing a specified initial coefficient (init_coef), initial exponent (init_exponent), and initial links forward and backward (init_fore and init_back).
polynode(
double init_coef = 0.0,
unsigned int init_exponent = 0,
polynode* init_fore = nullptr,
[Code] ....
I have no problem traversing at both forward and backward but not simultaneously. I can traverse forward, and traverse again forward with no problem. I can also traverse backward and traverse backward again with no problem (take note this is by not exiting the program). Without exiting the program, with the same datas inputed, if i traversed forward, i cannot traverse backward (it only gives me infinite loop of the first data) and vice versa.
#include <iostream>
using namespace std;
struct Node {
int data;
Node *next;
Node *prev;
[Code] ....
my code is
#include<stdio.h>
struct node {
int info;
struct node *next, *prev;
};
typedef struct node *nodeptr;
[Code] ....
I have reversed a linked list it is reversing but additional two elements 0,0 are coming, whats going wrong....
The program use a circular linked list and data structures to store the tasks.
- Every task should include a task name, a name for the person assigned to it, and the deadline for the task.
- Variables should be dynamic and their sizes should be determined at runtime based on the length of user input.
- You should implement the following functions (with appropriate arguments and return types) for your structure: add(), remove(), search(), and list().
- The add()function should add tasks alphabetically by task name. You do not need to implement any file operations.
- The search() function should be able search for a task by the task assignee name or the task name.
- The list() function should print records to the screen in the order they appear in the circular linked list.
- You should successfully deallocate all of the allocated memory before termination of your program.
I am trying to reverse a Linked list using recursion but whenever I try to print it after reversal it prints only the last element of the list.
Code:
void reverseRecursive(Node **root, Node *temp)
{
Node *next = temp->next;
if(temp->next == NULL)
{
*root = temp;
[Code]...
I have just posted the reverse function to enable easy readability rather than post the entire code
I am having trouble adding a second node to a doubly linked list. I define my list as follows:
Code:
typedef struct Node {
char command[256];
int length;
struct Node *prev;
struct Node *next;
} userInput;
}
[code]...
Now, when I iterate back through my list (I want to start at the tail and work my way towards the head), I can only ever get the 1st node to print, then the 2nd node is garbage, which means, to me, that I've linked something wrong.
I'm trying to write a program that manipulates a doubly linked list. My professor wants it to have two structs, one called Node (containing the data, and pointers to the next and previous nodes) and one called DLList, which contains the nodes for the head and tail (which is then passed to all of my functions).
I'm a little confused how to access the head and tail, for instance, if I want to initially set them to null in the main function (he emphasized the need for this), or to use them in my functions. I've tried a lot of variations to call the head and tail, but I keep getting told that head and tail are undeclared in the function.
How might I access my head and tail, for instance in a main function, when they're defined like this? (I took out all of the logic in my functions for clarity)
I need to delete the Nth node from a doubly linked list. I know I just cant delete it out right. I have all the goodies including a templetized node class. This is the code we're given:
template <typename T>
void doublyLinkedList<T>::deleteKthElement(const int item) {
}
It accepts an int, and should go to the Nth node and delete it.
i am trying to develop a doubly linked list class. I became stuck at a few of the functions as well as the main.cpp file. i have to insert a character sentence "TRICK OR TREAT" spaces included. I am stuck on the display and the listsize functions and im unsure if my insert has the head node in it. The function parameters were given to us and most of this code was given from a single linked list.
//node.h
#pragma once
class Node
{
publi
[Code].....
I'm not sure why my destructor isn't working..
typedef struct Node;
struct Node {
char data;
[Code]....
Why is it sufficient to only have a pointer to the last node of a doubly linked list?
View 1 Replies View RelatedCreate a notepad that allows the user to write text on the console. For this purpose, the user should be able to control and track the movement of the cursor. The user can access, add and delete any part of the text. To add or delete a text, the user can take the cursor to that location (using the arrow keys) and perform the required operation. The working of the program (i.e. the movement of the cursor, add and delete operation) must be consistent with the working of the real notepad. However, you do not have to handle word wrapping.
In addition, the user should be able to save and load the data in a text file using S and L respectively. The program will automatically save the data in file save.txt, and load the data from the same file. There is no need to ask the user for the file name. Use Q to quit the notepad. Don’t forget to implement the destructor.
Internally, the notepad is composed of two-dimensional doubly linkedlist. Its implementation is just like a doubly linked list with an additional property that it can grow in two dimensions. Since text can be written on multi lines, each row of the 2D-linkedlist represents one line. Each node contains four links which it uses to connect to node before, after, below and above it. In addition each node can store a character.
We had to convert a single-line text editor which uses arrays to one that uses OOP and double-linked lists and I have been doing it in steps. I have, for the sake of convenience, put my headers, implementation and main all in one file.
I'm compiling this program in Hercules (the getch function uses C code).
I keep getting the error from the compiler saying "Undefined Symbol" for functions:
insertNode(char, Node);
deleteNode(Node*);
insertHead(char);
The full message is: ld: fatal: Symbol Referencing Errors. No output written to a.out collect2: ld returned with 1 exit status.
// A fake single line text editor program.
#include <stdio.h>
#include <iostream>
#include <cstdlib>
#include <unistd.h>
#include <termios.h>
//#include "main.h"
typedef char Letter;
[code]....
I've been working on this linked list priority queue . I know that the root of the problem is in my swapUp() function (swapping the positioning of two nodes based on their priority), because the list works great up until it is called. The seg fault is not actually being caused by swapUp(), it's being caused by peekAt(), which returns the element in the node at position n. But the error does not occur unless swapUp() is called first, so that is where the issue is (I think).
There is also a seg fault being caused in the destructor, which I believe may have the same root cause in swapUp().
PRIORITY QUEUE:
#ifndef JMF_PriorityQueue
#define JMF_PriorityQueue
#include <iostream>
#include <string>
template <typename T>
class PriorityQueue{
[Code] .....
Okay, so I've tried implementing SwapUp() in a different new way, but it's still giving me the same problem
template <typename T>
void PriorityQueue<T>::swapUp(Node * target){
Node * partner = target->next; //Partner = target next
[Code] .....
This is such an elementary logic problem I don't know why I'm having so much trouble with it.
I've been working on a doubly linked list project for my Data Structures course. I've got everything to work so far, except for traversing in both directions. Traversing in the forward direction works fine, but when I try choosing to traverse backwards (starting from the tail of the linked list), it just says that the value is not in the list. That being said, the output looks like this:
This is not true, as you can obviously see, the value 26 is in the list, just two elements to the left of the tail (the value in tail for this particular case, obviously, is 36). The output should have been something like, "The value 26 was found 2 elements from the tail node". Here's the code for the findValue() function:
Code:
template <typename T>
bool LinkedListX<T>::findValue()//bool valueFound {
int traverseDirection = 0;
bool found = false;
int key;
[code]....
