C++ ::  delete Function Necessary When Allocation Fails?

I have a quick question about dynamic memory. I know that if you are dynamically allocating memory for a single data array and it fails, you can immediately abort the program via a return statement, but is this also true with multiple data arrays? For instance:

int *foo, *bar
foo = new (nothrow) int [5];
bar = new (nothrow) int [5];
if (foo == nullptr || bar == nullptr)
return -1;
else
/*rest of execution */

If the answer to the previous question is no, do you need to do a delete[] on the arrays that succeeded before terminating the application? Say foo is correctly allocated but bar fails, would you have to do something like this?

int *foo, *bar
foo = new (nothrow) int [5];
bar = new (nothrow) int [5];
if (foo == nullptr || bar == nullptr) {
if (foo == nullptr && bar != nullptr)
delete[] bar;

[Code] .....