When i set any 3 inputs length, the space should be move in right position. I try to fix the space move forward into 1 space, but don't know why it doesn't work. Specially, when the number is 4 or 5. The space didn't move 1 space.
using System;
class length{
static void Main(){
int i,j,k;
string star = "*";
string s1 ="";
string s2;
int[] nums = new int[] {3,4,5};
[Code] .....
I use photos to express it. The answer is:
Code:
int main(int argc, char *argv[], int n) {
int i,j;
for (i=1;i<=n/2+1;i++) {
[Code]....
I have been trying to make a small program that I will be using in a larger program that will make the user press space to see the next line of output.
Not exactly sure what I'm doing wrong, but I'm pretty sure that I need to put the space that the user would enter into an output file, and the read the input file
It runs, but it doesn't allow me press space before showing the next line.
I added a getline(cin, charVar) before, but I got a whole bunch of errors.
#include <iostream>
#include <string>
#include <cctype>
#include <cstdlib>
#include <fstream>
using namespace std;
// function for dialouge
[Code] ....
problem to draw magen david star ,i find code that draw pyramid of starts. how can i modify this code to receive magen david star ?
Code:
#include <stdio.h>
int main() {
int rows, star, spaces;
char bukva='A';
int number_of_stars = 6;
int number_of_rows = number_of_stars;
[Code]....
Consider a coordinate system for the Milky Way, in which the Earth is at (0; 0; 0). Model stars as points, and assume distances are in light years. The Milky Way consists of approximately 1012 stars, and their coordinates are stored in a file in comma-separated values (CSV) format one line per star and four fields per line, the first corresponding to an ID, and then three floating point numbers corresponding to the star location. How would you compute the k stars which are closest to the Earth? You have only a few megabytes of RAM.
View 1 Replies View RelatedI have written a star pyramid program, it adds two stars at a time but I want to rewrite the program so the stars double each time.
#include<iostream>
using namespace std;
int main() {
int a = 0, b = 8;
for (int c = 1; c < 10; c++) {
for (int space = b; space > 0; space--)
[Code] ...
I am trying to write a program that will make a pattern of stars. The last line is really tripping me up. I have to make the code only using the printf("*"); printf(" "); printf("/n"); statements once. I want to accomplish this with a for loops and if statements.
It is supposed to look like this:
* - 5 spaces before *
* * - 4 spaces before *
* * * - 3 spaces before *
* * * * * * - 0 spaces before *
This is what I've tried so far:
main()
{
int i, j, k;
i=1;
j=1;
[Code]....
here are the links on codepad [URL]
I think my first approach is way off. But I think I am on to something in the second link. I'm trying to print the "*" and extra 2 times on the fourth line. In the second link the compiler appears to be ignoring the || operator. Is my syntax incorrect in the second attempt? How should I change my if statement to make this pattern work?
Write a for loop statement to print the numbers from 1 to 10 in reverse order separated by star :
10*9*8*7*6*5*4*3*2*1
i try to do it but it show me like this :
10*9*8*7*6*5*4*3*2*1*
how do i write to show me like the first one ?
What the heck is wrong with my logic? I just print a rectangle!!! I have played with thing for ever it seems. I thought the rotating part would be hard but now I find myself stuck.
Code:
#include <istream>
#include "triangle.h"
using namespace std;
void triangle::create_triangle() {
[Code] ....
I originally had the user input three different lengths and then used this to determine whether or not it was a right triangle.
if(c==sqrt(a*a+b*b)||a==sqrt(b*b+c*c)||b=sqrt(a*a+b*b))
Now it has to be modified in order to accept the input 2,2 4,4 and 6,8(only an example) and be able to find out if it is a right triangle. I was told that arrays were not necessarily the only way to go about it.
I need to find out neighbors of a triangle and loop it over entire unstructured grid. How to do it?. Cell numbers are random so I am unable to loop over all cells.
View 9 Replies View RelatedI intended to compute perimeter of a triangle. The problem is the initial value for the triangle.
#include <iostream>
#include <cmath>
using namespace std;
struct Point{
double x;
double y;
[Code] ......
I expect to get 0 for triangle1, but I get some strange value...
Here is the result
Type x for point1 : 1
Type y for point1 : 1
Type x for point2 : 3
Type y for point2 : 1
Type x for point3 : 1
Type y for point3 : 3
The perimeter of the triangle1 is : 2.82843
The perimeter of the triangle2 is : 6.82843
After trying to understand the problem i finally gave up. The problem requires me to calculate the sum of the biggest numbers in a triangle.
For example: 5
4 0
3 8 2
2 7 9 6
Here is the solved problem from the book(It uses recursion, but i do not get it at all)
#include <iostream>
#include <fstream>
using namespace std;
int triunghi[50][50], n, sum=0;
int suma_max(int i, int j);
[Code] .....
I doesn't give me the same result(26) if a change the order of the numbers in the triangle.
Similar to Pascal’s triangle, the difference triangle has some interesting properties that find applications in various fields of the natural and applied sciences. In simple terms, a difference triangle is a set of integers arranged in an inverted triangle where each inverted triangle triad has its lower element equal to the difference (absolute value) of the two elements in the upper row. A difference triangle can be created from a sequence of integers forming the uppermost row by iteratively taking differences between consecutive terms to form the next row until a single-element row is created.
Example Consider the sequence 5, 8, 13, 21, 34, 55 from the Fibonacci series as the uppermost row of the difference triangle. The difference between successive elements form a new set: 3 (= 8 – 5), 5 (= 13 – 8), 8 (= 21 – 13), 13 (= 34 – 21), and 21 (= 55 – 34). The process can then be repeated until there is only one element left giving the following difference triangle:
5 8 13 21 34 55
3 5 8 13 21
2 3 5 8
1 2 3
1 1
0
Problem Write a program that forms a difference triangle using a given series of numbers as topmost row.
Write a class called MyTriangle, which models a triangle with 3 vertices, is designed as follows. It contains:
1. The MyTriangle class uses three MyPoint instances as the three vertices.
2. Three private instance variables v1, v2, v3 (instances of MyPoint), for the three vertices.
3. A constructor that constructs a MyTriangle with three points v1=(x1, y1), v2=(x2, y2), v3=(x3, y3).
4. An overloaded constructor that constructs MyTriangle given three instances of MyPoint.
5. A toString() function that returns a string description of the instance in the format "Triangle @ (x1, y1), (x2, y2), (x3, y3)".
6. A getPerimeter() function that returns the length of the perimeter in double. You should use the distance() method of MyPoint to compute the perimeter.
7. Also write a test program (called main.cpp) to test all the functions defined in the class (example of a triangle: (-2, 1), (1, 3) and (3, -3)).
class MyTriangle {
MyPoint v1;
MyPoint v2;
MyPoint v3;
public:
MyTriangle(int x1,int y1,int x2,int y2,int x3,int y3) {
[Code] .....
I was asked to build a small program to calculate the are of a Triangle but my code must have some problem.. />
#include "stdafx.h"
void main()
{
int a,b;
[Code]....
I get this errors:
-warning C4996: 'scanf': This function or variable may be unsafe. Consider using scanf_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS.
-warning C4244: '=' : conversion from 'int' to 'float', possible loss of data
I wrote a function to calculate the hypotenuse of a triangle. My code looks fine but when i enter the two sides it does not give out the right answer. I really don't know what to do.
#include <stdio.h>
#include<Windows.h>
#include<math.h>
double hypotenuse(double side1, double side2);
int main(void){
double side1, side2, hyp;
[Code] .....
So, I have created a class called "point" and i have 4 "point" objects. They only have 2 variables, x and y (their position). The first 3 points form a triangle and now I need to tell if the forth one is inside or outside. I have found some solutions but they involve heavy math (they are based on the sum of the angles or something like that). I want to know if there is any way to solve this only by using the distance between points. I have created a function which takes 2 "point" objects and returns a float value which is their distance.
Here is some code:
#include <iostream>
#include <cstdlib>
#include <math.h>
using namespace std;
[Code]....
how to input with space what i mean is like this, for example:
Product Code: 0000001
Product Name: Mobile Phone
if the users input is like that in the (Product Name)it will skip the next input that is the
Price: Quantity: 100
Manufacturer: Alcatel
something like that...
Heres the code
Code:
if(b<=10)
{/*Start for IF Statement*/
for(a=1;a<=b;a++)
{/*Start of FOR loop*/
printf("
");
printf("Product Code : ");
scanf("%s", &prod_code);
}
[code]....
I used pointer(or is it not?) to make it one part only alphabets and the other one digits. The coding, calculate_charges.c and the open file, customer.txt are attached at the end of the post.
Code:
#include <stdio.h>
#include <string.h>
#define SIZE 3
void trimback(char input[], int strnameindex);
void trimfrnt(char input[], int strnameindex);
}
[code]....
What would the worst, average and best case space complexity be for a data structure of type map<string, vector<int> > in big O notation? I'm parsing through a document and storing each word as a key and im attaching an associated int (in a vector) to it as the value.
View 4 Replies View RelatedI'm making a program that prints a triangle of @ signs given rows (but not columns).
For example, the output with rows = 4 would be:
@@@@
@@@
@@
@
and rows = 3 would be:
@@@
@@
@
However, trying to make this has given me a program that does something similar (but not the same):
for example, with my current program rows = 4 outputs:
@@@@
@@@
@@
@
and rows = 3 gives
@@@
@@
@
It seems that it's just missing a space (and therefore a setw and setfill), but I found 2 problems:
1. The space needs to not apply to the first line.
2. I can't get it to make a space before each row without making a space between each column.
My current code is:
#include <iostream>
#include <iomanip>
using namespace std;
int main ( ) {
int rows;
[Code] ....
I have tried putting in << setws and << setfills of various values but it seems to always apply to between each column as well as at the start of each row- what do I do?
I have a program that prints out pascal's triangle. One problem: it isn't a triangle. The output doesn't work. This is what it should print:
Code: How many rows: 4
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1 and this is what it does print: Code: Enter a number of rows: 4
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
[Code]....
I am currently learning "if statements" while doing a program that calculates the area of a triangle. My problem is that the result is always "0". I am pretty sure the problem lies within my math, but how I have set it up wrong.
I am using Heron's Formula. Here it is for reference:
area=sqrt(s(s-a)(s-b)(s-c)) where s=(a+b+c)/2
Code:
#include <stdio.h>
#include <math.h>
int main () {
float area, sideA, sideB, sideC, halfP;
[Code] ....
How to do the function part here is the question. "Write a program that calculates the hypotenuse of a right triangle. the program should ask the users to enter the length of the two legs of the right triangle and the program should call a function hypotenuse() that will calculate and display the length of of the hypotenuse. NOTE: The program should include a prototype for the function hypotenuse()" i have this so far
#include <iostream>
4 #include <cmath> // Needed to use the sqrt function
5 using namespace std;
6
7 int main()
8 {
9 double a, b, c;
[Code] ....
How to make triangles using c++, in nested while loops.
The triangles were:
*
**
***
****
*****
******
*******
********
*********
**********
I have made a code for this:
int counter=1;
while (counter<=10){
int counter2=1;
while (counter2<counter){
[Code] .....
I was not quite sure about this one.
