So i have this -
time_t t4 = time(NULL);
//and then some stuff
time_t t5 = time(NULL);
iElapsedYah = t5-t4;
fElapsedYah2 = iElapsedYah/iNumTimes;
printf("It took %f seconds", fElapsedYah2);
but it always prints 0.0000000, and i dont know why even though individually
iElapsedYah = not zero and iNumTimes = not zero
I am using windows 7 and m complier is Dev C++
I have a program that makes change from an amount. It works fine, but the output is the correct output looped over and over. I have tried everything, but it still doesn't work. For example, a amount of 98 should print
3 quarters
2 dimes
0 nickles
3 pennies
but instead it prints
3 quarters
2 dimes
0 nickels
3 pennies
0 quarters
2 dimes
0 nickels
3 pennies
0 quarters
2 dimes
0 nickels
3 pennies
Why it's doing this?
Code:
#include <iostream>
using namespace std;
int coinscount(int& amount, int value) {
int tracker = 0;
int amountdimes = amount;
[Code].....
I have a program where the user inputs a line of integers, and then all unique ones are outputted. It works fine-almost. It prints the numbers correctly, but prints them more than once and I'm not sure why.
Code: #include <iostream>
using namespace std;
int main ( ) {
[Code]......
Is there a variable that can hold string and int in the same time?
If not, what can I do if I want to input data with string and int like a password for an example.
In a function, I have a static variable that I want to assign the time in seconds when a certain condition is met and keep that value until a different condition is met. The time value is a struct. Since now->sec is always incrementing, will timeWhenEventMadeActive below hold onto the initial value or will it increment every time the function is called? I cant seem to test this.
static time_t timeWhenEventMadeActive = 0;
static bool initTime = 0;
if (!initTime) {
timeWhenEventMadeActive = now->sec; //holds uptime value in seconds
[Code] .....
i need to display the current time and date in my program and use variable to store each of the time values like
a = 10
b = 29
c = 31
printf(``%d : %d : %d``, a,b,c);
which then give the output as - 10:29:31
How to save the time in variables in C....
i am using C in windows 7 and my complier is Bloodshed Dev C++
i am relatively new to C programming so i run into problems on daily basis. But this time i have something i just cant figuer out and i was hoping you could point me towards the right track. I am trying to divide two integers.DevValue by KpTotal. for some reason my micro controller allways crashes.Y is a variable of a distance measuring sensor. i have a 4x4 keypad to enter a three digit number (e.i 123) so Kp1 = 1 Kp2 = 2 Kp3 =3.
Code:
int kp1, kp2, kp3, kpTotal = 0;
char txt[6] = ""
int keypadPort at PORTD;
sbit LCD_RS at RB4_bit;
sbit LCD_EN at RB5_bit;
}
[code]....
i think it has something to do with the format of the value. i read that the micro controller crash when dividing by zero.
I wrote the following code to divide 100 customers into three clusters but it kept on hanging during execution. I used while loop. Attached is the text file to use. and the code below :
#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
#include <stdlib.h>
#include <cstdlib>
#include <ctime>
#include <stdio.h>
#include <math.h>
[Code] ....
Attached File(s)
c201.txt (7.13K)
i made a calculator that you have to give terms and operators one by one but now i want to improve it. the user now should be able to type something like 5*78+325/sin(3*pi)-1 and the program should be able to calculate it. but i don't know how to use the signs '*','+','-' and '/' as delimiters and turn the input string into a string array. i mean the string "5*78+325/sin(3*pi)-1" will become a string array like "5,*,78,+,325,/,sin(3*pi),-,1,"
View 2 Replies View RelatedI need to read a float number and show the rest of his division by an integer, but i'm having the following error message:
Quote
error: invalid operands of types 'float' and 'int' to binary 'operator%'
So I have a simple calculator that does a few operations (+ - * / %) Pretty basic stuff
I declared int x, y for the numbers, char operation, and float result.
the code is based on switch(operation)
The program is running alright, but when I divide 8/7 it returns 1 as the result, I tried changing the x and y to float but that won't work because of the case '%'
I also tried making local float variables in the case'/' but it won't compile "E2126 Case bypasses initialization of a local variable"
How can I make the division work and return a float value?
I'm supposed to store the value of a countrys population. Then gather out the percentage that countrys population holds when compared with the global population.
Anyway here's the code:
Code:
#include <iostream>
long swe_pop = 9644864;
int main ()
[Code] .....
The result I'm getting is 0%.
I was under the impression that long (or long long) integers could hold high values. And that I could then divide these and answer with a float type value. Giving space for the decimals.
Im using the remquo function in the cmath library as follows:
int quotient;
double a = remquo (10.3, 4.5, "ient);
This gives the correct remainder (a = 1.3) and quotient (quotient = 2).
Infact about 50% of the answers are right when I play around, however, trying something like:
int quotient;
double a = remquo (2.25, 1.5, "ient);
yields an incorrect quotient of 2 and remainder of 0.
I do think this has something to do with float arithmetic. I recall tinkering with the float number 0.500 and that the CPU actually saves it as 0.50000000000000231. However if my suspicion of float arithmetic as the suspect is correct, I do not understand why a tenth decimal would make such a drastic difference as changing the quotient result.
I'm writing a program to calculate a final grade by adding 4 numbers minus the lowest grade and dividing by 3. My knowledge in c is not extensive I thought that a simple assigment operator would do the job but I'm getting a strange large numbers in the execution.
Code:
#include <stdio.h>
#include <stdlib.h>
main(){
int eg, g1, g2, g3, g4, fg, s1, s2, sg;
[Code] ....
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h>
int main(){
int i,j=0,n,time,remain,flag=0,ts;
int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10];
int ganttP[50],ganttStartTime[50];
printf("Enter no of Processes : ");
scanf("%d",&n);
remain=n;
[Code] ....
When I run this code
#include <stdio.h>
int main(int argc, char* argv[])
{
int i=0;
int count=0;
while(i<5)
i++;
count++;
printf("The value of count is: %d", count);
return 0;
}
It only prints: The value of count is 1. I'm confused on why it doesnt print the value of the count is 5
So I'm trying to learn how to use time for time based movement and what not. I did this only knowing the command time(&variable)
time_t timer;
int I, X;
void main() {
time(&timer);
X=timer;
while(I==5) {
[Code] ......
There's probably some other better way to do it... Obviously but for now I see it as putting current time in X.
start while
take in time constantly until I is 5
constantly asking is time>X(preset time 5 seconds ahead)
if it is
display message and add one to I
Why doesn't this display my message after 5 seconds?
I need to make a program that prints certain pictures. My program compiles successfully. However, I cannot figure out how to view the ppm output. When i run the program i get a lot of random text.
View 2 Replies View RelatedI'm making a program that prints a triangle of @ signs given rows (but not columns).
For example, the output with rows = 4 would be:
@@@@
@@@
@@
@
and rows = 3 would be:
@@@
@@
@
However, trying to make this has given me a program that does something similar (but not the same):
for example, with my current program rows = 4 outputs:
@@@@
@@@
@@
@
and rows = 3 gives
@@@
@@
@
It seems that it's just missing a space (and therefore a setw and setfill), but I found 2 problems:
1. The space needs to not apply to the first line.
2. I can't get it to make a space before each row without making a space between each column.
My current code is:
#include <iostream>
#include <iomanip>
using namespace std;
int main ( ) {
int rows;
[Code] ....
I have tried putting in << setws and << setfills of various values but it seems to always apply to between each column as well as at the start of each row- what do I do?
I have a program that prints out pascal's triangle. One problem: it isn't a triangle. The output doesn't work. This is what it should print:
Code: How many rows: 4
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1 and this is what it does print: Code: Enter a number of rows: 4
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
[Code]....
output should look like this -
So far i have this
[code]#include <iostream>
#include <time.h>
using namespace std;
int main() {
srand(time(NULL));
[Code] .....
I am getting these errors when i compile it
random.cpp: In function âint main()â:
random.cpp:23: error: expected â,â or â;â before numeric constant
random.cpp:24: error: âRâ was not declared in this scope
random.cpp:25: error: âRâ was not declared in this scope
random.cpp:26: error: âRâ was not declared in this scope
random.cpp:27: error: âRâ was not declared in this scope
random.cpp:28: error: âRâ was not declared in this scope
So I need to make a program that reads distance and number of days of a person that is buying a ticket. If distance is greater than 1,000 kilometers AND the person stays more than 7 days, the discount is 30% of the ticket. The cost per kilometer is $1300. Print the ticket with discount.
I used variable distance as float because it will be multiplied with 0.3 for the discount... not sure if I'm right on that.
Code:
#include <iostream>
#include <conio.h>
using namespace std;
int main() {
float distance;
int days;
[Code] .....
I tried another way but haven't done it in code...
ask for distance
ask for days
Ticket= (Dist x 2 x $1300)
If (dist>1000) && (days>7)
cout<<Ticket=Ticket * 0.3;
else { cout<<Ticket;
#include <iostream>
using namespace std;
int main()
{
int num = 2;
int count = 0;
while (num <= 100)
[Code]...
The code works fine but I need the results to print out like
2 4 6 8 10 12 14 16 18 20
22 24 26 28 30 32 34 36 38 40
instead of
2
4
6
8
10
12
I don't know how to do this.
Im trying to make a Tic Tac Toe board for an assignment. Right now it compiles fine but when I enter an x or o it does not update the board it just prints out the '.'s that the board is initialized to. Also, when I get to player 2 the board will printout twice so its 6 rows or 3 columns. The project uses a main to ask who starts then goes to a play function that asks for inputs and calls the makeMove function to place the x's and o's and the print function to display the updated board.
bool Board::makeMove(int rowIn, int columnIn, char currentPlayer) {
if (playBoard[rowIn][columnIn] == '.') {
playBoard[rowIn][columnIn] = currentPlayer;
return true;
[Code] ....
The print statement below I commented prints out unusual characters. I have two strings from the command line that I pass to the TKCreate function. Inside the function the strings print out fine, but when I return a pointer to the struct back to the main method one of the strings prints out fine, but the other one prints out unusual inconsistent characters.
#include <stdio.h>
#include <stddef.h>
#include <stdlib.h>
#include <string.h>
[Code]....
Is there a way/code to get my computer's IP address and prints it without using ipconfig
Example: My computer's IP address is: 198.110.69, it will print an output: 198.110.69 or 19811069 (without dots would be better though) ....