I want calculate sum of every digit in my zip code so I wrote implementation function like that but, it shows "0" as answers, then I realize it should be call first, I add correctionDigitOf() in to constructor "Zipcode::Zipcode" then My zipcode are all "0' after I do this .....
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <ctime>
#include <cmath>
using namespace std;
class Zipcode {
[Code] ....
Write a function which will take 3 arguments. The function needs to return a new number which is formed by replacing the digit on a given position in the number with a digit which is carried as an argument (the position in the number is counted from right to left, starting with one). Write a main program which will print the newly formed number.
Examples:
A function call of 2376, 3 and 5 should return the number 2576
A function call of 123456, 4 and 9 should return the number 129456
What I succeeded to do so far:
Figure out the logic for swapping the digit and write working code for it (in the main function).
What I failed to do so far:
Write a function which will return the desired result.
What is my problem:
I tried writing a function to do this, but as you see from my calculations, my result is divided in 3 parts. I don't know how to return more variables from a function.
Code:
#include <stdio.h>
int main() {
int inputNumber, swapPosition, swapDigit;
scanf("%d%d%d", &inputNumber, &swapPosition, &swapDigit);
int i, numberPart1 = inputNumber;
for (i = 1; i <= swapPosition; i++)
[Code] ...
I want to prevent to type zero as the first digit in value in c code
Code:
char next_buffer[ 5 ];
int frame_counter;
int digit_counter;
memset( cmd->next_buffer, 0, sizeof( cmd->next_buffer ) );
cmd->frame_counter = 0;
cmd->digit_counter = 0; Code: if( arg && isdigit( arg[ 0 ] ) {
[Code].....
this write in text box numbers from keypad for example
5 0 2 4 9
After each typed digit, here is a underscore line waiting for the next to type next digit. I want to prevent users to type zero as the first digit in value.
I wanted to find all the prime until a specified limit in C. I use the Sieve of Eratosthenes. But when I define the limit to anything more than a 7 digit number the program terminates.
Code:
#include<stdio.h>
#define limit 1000000000
int main(void)
{
unsigned long long int i,j;
int primes[limit] = {0};
//int count =0;
for(i=2;i<limit;i++)
}
[code]....
I believe that this might be because the size cannot be declared array cannot be more than the a 7 digit number. I think so. how to store a 10 digit number in C?And can't unsigned long long hold a 10 digit?
I have an array join[], some of its elements are single digit and some are numbers. I want to print the output in single digit form.Like in below code
Code:
int join[3]= {12,0,3};
int split;
int j;
for (j=0;j<3; j++) {
[Code] ....
My code won't consider array element "0". How can i fix it for that too.
Code: I want output should be like
1
2
0
3
I am trying to remove the first digit so if the user enters 12345 it should output 2345 the code i have works only for removing the last digit how would i go about removing the first one?
#include <iostream>
using namespace std;
int removeFirst(int n);
int main(){
int n, m;
cout << "enter number" << endl;
[Code] ....
this code :
#include <cstdlib>
#include <iostream>
#define TRUE 1
#define FALSE 0
using namespace std;
typedef int Bool;
[Code] ....
Gives repeated digits in an integer but only in one condition : Only if the repeated digit is the result of n%10 where n is the integer the user writes. If the repeated digit is not the result of n%10 , then the compiler gives a wrong result.
so the question is : how to make this code gives the repeated digit in an integer (regardless the fact that the repeated digit is the result of n%10 or not and especially with making the minimum of changes on the code)????????? ?????
My question is why my on my code there is 10 zip code and i want to show the first digit, the problem is the first digit does not match the zip code for example the zip code is 45805 it should be '5' however, my code shows other number!
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
[Code].....
what is the data type of a variable to store 50 digit number in c? and what is the data type specifier for that?
View 5 Replies View Relatedi just started learning programming and i just wanna know how come when i try to print the last digit of a number the output always become 6?
View 4 Replies View RelatedSo I have to ask the user to enter a positive 12 digit number, and it has to be 12 digits exactly. I thought I'd do
Code:
unsigned long long int x;
do{...}
while(!(x>99999999999 && x<1000000000000));
This would obviously be fine on my 64 bit machine, but the code will be ran on a 32 bit one, where unsigned long long is, if I'm not mistaken, 32 bits. Which has a max value of 4 billion and something.
Assignment: Take an integer keyed in from the terminal and extract and display each digit of the integer in English. Ex. 932 --> nine three two
Code:
/*This program takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English.*/
#include<stdio.h>
int main(void)
{
//DECLARE VARIABLES
int num;
}
[code]....
I don't know how the program works if the integer is more than one digit.
How to get all the possible combinations for 4 digits from a 5 digit number. I need a pair that has both 5 digits and four digits. their sum must be equal to a five digit user input. i.e.
user input : 14690
output:
14690 has pairs 12345 + 2345
2345 came from 12345
lets say that x = 12345 and y =2345
besides y == x%10000
other formula can i have since if i use % and / i will have a lot of declarations....
I am trying to redefine an array, but the result can only display one digit variable. I want the program to display 97 98 99 *+, but the program is only displaying 789*+.
int main() {
string test="abc*+";
for(int i=0; i<test.size;i++)
[Code].....
So I want to do the following, I want to input 150 1 digit integers, from 0-9 and I don't want to put spaces between them while inputing, like if I input a 150 digit integer, the compiler should take it as 150 1 digit integers. I'm not sure how to accomplish that.
int a[150];
for(int i=0;i<150;i++)
cin>>a[i];
If I try to do it with above code, the compiler needs a space to know when the value of i is incremented. But I want to avoid spaces for my task.
How to produce a code that will satisfy the following constraints. I don't really know C++
- Produces a random three number positive integer between 001 - 504.
- Changes the output number every 24 hours on a website.
I want to encrypt Mac address to 4 digit number which can be decrypted to original MAC address.
View 9 Replies View Relatedif i have two integers, say number1 and number2, stored in arrays where each index is a digit of the number (i.e. if my numbers are 321 and 158, then number1 = {3,2,1} and number2 = {1,5,8}), can i find the remainder of number1/number2? assume number1 > number2.
View 1 Replies View RelatedWith out sorting and if the array size is changed and filled with different elements, mayb some that are all duplicates(in that case display message that says "No nonrepeated digits".
This seemed like a simple task but im failing to grasp some concept. if the array is 2,0,38,2,3,1,3 the first non repeated is 0.
nested loop is how i went. i feel like im going to far with the counters than need be. just need first non repeated. if n equals 2 an o equals 0. and it iterates comparing 0,38,2,3,1,3 to n which is 2. repCount will b 1. if repcount was 0 then n would be the first non repeated number. im trying to consolidate my if else statements so there are not so many. This program fails if the array gets bigger say 2,45,2,7,1,8,9,45,1,10 .....
for (n=0; n<sizeof(digits)/sizeof(int); n++) {
if(repCount<2) {
// nonRepCount=0;
for (o=n+1; o<sizeof(digits)/sizeof(int); o++)
[Code] .....
I can't find the highest digit within c-string. Ithe user was to enter 1234. the highest shall be 4 but can't get that number.
int Hnum(char* str) {
//int size = 0;
int H = 0, remainder, div =0;
int intstr = atoi(str);
[Code] ....
I am trying to write up something to have a user to enter a four digit number. Only four digits, Ex: 0001, 0116, or 9999. There is no getting around the selection 0001 or 0002. I understand if not done correctly, the first three 0's will be ignored.
I've been just playing around with what I have below but I just don't remember how to do it nor can I find a good example online to figure it out. I know it is not correct just typing to try to remember. I am aware that it is gibberish right now, this is just me brainstorming.
int number;
cout<<("Please enter the four digit number(Ex: 0001):
");
cin>> setw(2) >> number;
cout<<)"Please enter four digit date. Two digits for month and two digits for year:
");
cin>> date;
if (number< || number > 30)
cout << "Invalid choice. Try again." << endl;
cin.clear();
I've seen some threads that include the information about what data types one has to use usually to put a number of 12digit. But honestly speaking none of them works for me & it takes me a lot suffering about the data type. Even I've googled but I didn't get any specific result.
So, which data type I'd have to use to enter 12digit number.
I'm writing a code to find the largest prime factor of the number 600851475143
I need to create a program that lists off each digit of an integer and then display the sum off all the digits in that integer. I know that sepereatly the sum function i wrote works. But the first part which i try to list off the digits work but in reverse order which i dont know how to correct. and for some reason that i cant figure out this is affecting the sum output.
#include <iostream>
using namespace std;
int digcount (int x) {;
[Code]....
I have been working on some C++ code that doesn't seem to be going right. I'm wanting it to read a (three-digit) integer representing the value to be encrypted, a (one-digit) integer representing the encryption key, encrypt the value and print the encrypted value. The encrypting method used is that each digit in the given number is replaced by ((the sum of that digit plus key) modulo 10) then the first and last “encrypted” digits are swapped.
For example, if the number entered was 216 and the key given was 7, after applying the encryption procedure described the first digit (2) would become 9, the middle digit (1) would become 8 and the last digit (6) would become 3. The first and last encrypted digits are then swapped. The program displays the encrypted number: that is 389 in this case.
#include <iostream>
using namespace std;
int main() {
int isolateDigits();
int replaceDigits();
int swapDigit1withDigit3();
[Code] ....
Return the digit at the user specified index of an integer. If the integer has n digits and the index is NOT in the range 0 <=index <n return -1 Start the digit numbering at 0. Example, if user input is 4 (index) and the integer equals 123456790 the return value for the function is 5 (start index at 0) ; if user input is 40 (index) and the integer equals 123456790 the return value for the function is -1
#include <iostream>
#include <istream>
#include <cstdlib>
#include <cassert>
#include <string>
using namespace std;
int getIndex(int, int);
[Code] .....
I have this example problem in my school coursebook. How this program works? It determines the highest digit in a number.
#include <iostream>
using namespace std;
int m(int n) {
int a,b;
[Code] ....
