my lecture notes had this chunk of code on it. Which was the way to let a user enter not more than 40 different numbers , and save it into an array. The code is as follows :
#include <stdio.h>
#define MAX 41
void readData(int num[] , int * count);
[Code]...
In the function readData , why is n being scanned before and during the while loop?
I am trying to code and compile a program that requests a uses to first inpu the number of sides they wish for a dice to have and secondly input the number of dice throws they would like to calculate the value for. The program will print an error message and default the number of sides the dice has to 5 if the number entered is below 4. Finally it will print out a percentage figure for each value that results from all the the dice rolls.
I have attached my header, driver and class files below along with accompanying error messages below them
// file name Exercise.cpp
#include <iostream>
#include "Die.h"
using namespace std;
int main() // the main program begins here
{
char restart = 'y'; // declare variables
double numRolls = 0.0;
int diceTot = 0;
[Code] .....
Code:
#include <stdio.h>
int main(){
int A, B;
char decision;
printf("Do you have an integer to input? [Y/N]: ");
scanf("%c",&decision);
if(decision=='Y' || decision=='y'){
[Code]....
After entering a single integer, it doesn't scan again for another integer. What's wrong?
I'm using a mac btw, if that makes a difference with Ubuntu/Linux.
I have learnt recently how to use fgetc, fputc, fputs, fgets but still I am not able to figure out how to read values from a file like for example:
12 14 1928 32993932
17 98
166 109 201
These are separate integers & i want to read them and then manipulate these individual integers like going for 2*I1, 4*I2 and so on where I1 and I2 are 12 & 14.
I want to have calculations take place inside a switch statement that calls the appropriate function. The menu portion of the program works well, but I can't figure out how to let the user actually input 2 different numbers to the functions. My questions are:
1. If I use scanf to assign values to the variables, what determines end of input to each variable? (ie.. scanf("%d%d", &a, &b) what is the end of a, what is the end of b?)
2. Should I assign the variables to user input inside the switch, or try to do it in the functions below?
3. Is there something I haven't thought to ask that will screw me over? I'm really new to this.
Code:
#include<stdio.h>
int add(int b, int a);
int mult(int b, int a);
main() {
[Code] ....
This really was a test of multilayer menu, but I want to add functionality if I can.
Changed a variable before posting and didn't change all the conditions testing it.
On my program I use a counter to count to 10, then i ask for a string, in this case "yes" or "no", during the count, i want to keep the user from putting inputs in, due to the fact that if they put both "yes" and "no" before the program reads the string.
Code:
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#include <stdbool.h>
#include <time.h>
#include <string.h>
}
[code]....
it skips the input phase,, instead of inputting the last name it goes directly to the firstname then middle initail and street name are working fine but it skips the street name then goes to city and so on....
Code:
char l[50], f[50], m;char strtname[50], cty[50], cntry[50];
int strtnum, zp, i;
system("cls");
printf("Enter Last name:");
gets(l);
printf("
Enter First name:");
}
[code]....
I have a project that requires I take user input from menu options and put it into an array which I will average out. I can set the menu up I think, but I cannot understand how to put what the user inputs into an array. Granted I just took the lecture on arrays today. Also we can only use functions to do the work.
View 9 Replies View RelatedI don't know how many numbers will be the input only that its going to be up to 10000. EOF should be active. I tried it like this:
Code:
int i = 0;
int del[10000]
while (scanf("%d",del[i])!=EOF)
{
i++;
}
But it seems the value of i doesn't increment, could you provide some tips on how to scanf the inputs into an array if I don't know how many numbers will I have?
Any chances for a c program to check for browser inputs?
View 1 Replies View RelatedFor a program I am required to use a cin that accepts 4 variables. The first describes a function such as add(), remove(), print(), or quit(). The problem is that to use add() I need to input all 4 variables but for remove(), only 2 variable input is needed.
I want the input to be "add 9 James Bond"
or be "remove 341"
Here is my current code.
int command(string command, int Id, string first, string last){
while (command != "quit"){
cout << "customers> ";
cin >> command >> Id >> first >> last;
if (command == "add")
[Code] .....
I am new to C++ and I want to learn how to set color a particular color for the users input and output. For example, I want to display the users input as green, and their output as red.
View 2 Replies View RelatedHow to combine the if statements?
cout<<"Enter a sale number"<<endl;
cin>>rec.sale;
if(cin.fail())
{
cout<<"Enter a number"<<endl;
cin>>rec.sale;
}
[Code]...
How to use library management inputs
View 2 Replies View RelatedMake a C++ Program that will use nested if else and any looping statement to display the following a certain number of times depending on how many times the user wants it to do so.
Input Values:
1. Name of employee
2. Position in the company
3. No. of hours worked
4. Rate per hour
5. Overtime hours
Required Output:
No. Name Position Rate per No. of hours Basic No. of overtime Overtime
hour worked Pay hours Pay
1. Juan Manager 160 140 22400 10 2100
Computations:
basic pay = no. hours worked x rate per hour
overtime = overtime hours x 150% of rate per hour
Just asking how can I input the name, position, rate per hour, overtime hours and hours worked in a horizontal manner?
Because I need to achieve the required output.
How to make an input with a string thats part of an if statement. How I think it should be done :
#include <iostream>
#include <string>
using namespace std;
int main() {
string choose;
[Code] .....
But I get a strange warning (not an error, but something that is like "just letting you know" i suppose) and when i enter in ss or SS or aa or AA, it breaks my app.
How to get user inputs into an array. I have to get 10 user inputs into the array and I'm trying to use a loop but once I run it it crashes whenever you input the first value. This is my absolute first time working with arrays and I've been trying to do research
#include <stdio.h>
#define SIZE 10
void Input(const int array1[]);
void Calculations(int array1[], int average);
void Output(int array1[], int average);
[Code]....
It's not something trivial but I would like to know the best way to process multiple outputs, for example:
Input
First line of input will contain a number T = number of test cases. Following lines will contain a string each.
Output
For each string, print on a single line, "UNIQUE" - if the characters are all unique, else print "NOT UNIQUE"
Sample Input
3
DELHI
london
#include<iostream>
Sample Output
UNIQUE
NOT UNIQUE
NOT UNIQUE
So how can I accomplish outputs like that? My code so far is:
Code:
int main(int argc, char *argv[]) {
int inputs, count=0;
char str[100];
char *ptr;
scanf("%d",&inputs);
[Code] ....
But the above will obviously print the output after each input, so I want to know how can I achieve the result given in the problem. Also another thing I want to know is, I am using an array of 100 char, which it can hold a string up to 100 characters, but what do I have to do if I want to handle string with no limit? Just declaring char *str is no good, so what to do?
I have recently looked into a self created project where I wanted to compare user input against a list of strings in an external file. That has since been completed to my great satisfaction, however it did throw up some interesting issues in my knowledge and understanding of user input..What is the best way to pick up user input i.e scanf,stdin etc. and when should either be used and can a mixture of types be used, and if so, when and why.
A quick program to take different input methods and display differnt output method (obviously corresponding i.e scanf/printf - fgets/fputs)
My first pothole came when I have setup the method for scanf - fine. Then I setup the method for fgets(test,100,stdin) for example and the fgets method no longer picks up stdin from the user..
I am beginner at C and I was working on a program where I have to read in a line such as Digit, String, Float. The string can have any amount of spaces between it. and each input is separated by a space character.
The input is of the format:
10000000000 hello my n ame is 30.2
So I used fgets(x,100,stdin) to read the line in.
So I need to read that line into an int, array, and float.. so I was thinking of using this:
sscanf(x, "%d %[^/n] %f", &number, &username, &numberfloat);
Now, obviously I can't use the /n to read in the username with spaces because I need to read the 30.2 into a float variable.
This is just a portion of my program and I want to trap the integer inputs using while loop.
cout<<"
Enter the name : ";
while(/*integer input or not in character*/) {
//Invalid Input!
}
cin.ignore();
cin.getline(name, 100);
I'm fairly new to C++ programming. I wanted to accept a datatype as an input. I've seen something similar while working with the <queue> library.
When defining a new object of queue
For example:
queue<int> Queue;
How is <int> handled ??
Write a function which takes two parameter of integer type and both parameters are positive integer. These number should be provided by the user of your program. The first parameter is lower than the second parameter. You function should be able to calculate the sum of the square of each of the numbers between the two inputs and should display that. Please write a main function to display the working of your function. Call the function at least three times by using some loop in the main function.
This is what I came up with but it is not correct:
#include <iostream>
using namespace std;
void sumsquares(int number1, int number2) {
int sum = 0;
for(int i = number1; i<number2; i++)
sum =sum+ i*i;
cout<<"The Result is: "<<sum<<endl;
[Code] .....
How to calculate the values between numbers that a user types in.
Write a function which takes two parameter of integer type and both parameters are positive integer. These number should be provided by the user of your program. The first parameter is lower than the second parameter. You function should be able to calculate the sum of the square of each of the numbers between the two inputs and should display that. Please write a main function to display the working of your function. Call the function at least three times by using some loop in the main function.
I have an assignment where we have to input this sample code and get the following results:
./lab3
Please enter the vectors here:
1 2 3 4 2 s
You are not giving even number of inputs!
./lab3
Please enter the vectors here:
1 2 3 2 4 4 s
The sample values are:
1 2 3
The frequencies are:
2 4 4
The discrete probability distribution is:
0.2 0.4 0.4
The mean is 2.2.
The variance is 0.56.
-----------
I got the part with the mean, variance , and probability distribution but i cannot split up user input into vectors for sample values and frequencies.
"1 2 3" are suppose to become sample values and "2 4 4" are suppose to become the frequencies.
------------
------------
I also wanted to know how to properly make the code so if there is an odd number of inputs the code outputs "You are not giving even number of inputs!". But if is an even number of inputs the code runs. To do this I have:
int main(int argc, char** argv){
float input = 1.0;
cout<<"Please enter vectors here:"
cin>>input;
[Code] ....
How can i set up an error check so only letters are entered? I know how to do it for numbers but how to make it so it only allows a-z inputs.
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